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kaheart [24]
2 years ago
12

Malik formed a hypothesis that an increase in atmospheric oxygen levels by 10% would cause red-legged grasshoppers to grow large

r than normal. Suppose that Malik performs an experiment to test his hypothesis. Which of these actions would represent a scientific mistake in his experiment?
He experiments on live grasshoppers instead of preserved ones.
He focuses on red-legged grasshoppers instead of all kinds of grasshoppers.
He varies the nitrogen and carbon dioxide levels in the air from one trial to the next.
He conducts the experiment in a controlled lab setting with a lab partner.
He measures the mass and length of his specimens at the start of each trial.
Physics
2 answers:
worty [1.4K]2 years ago
8 0
<h2>Answer:</h2>

The option C is the correct answer.

Which is, "He varies the nitrogen and carbon dioxide levels in the air from one trial to the next".

<h3>Explanation:</h3>

The hypothesis of Malik was about the effect of increased oxygen level on the growth of the red-legged grasshoppers.

So the areas of his experiment should be the:

  • Grasshopper type.
  • High oxygen level.
  • Rate of growth of grasshopper.

So all the given options are relevant to his experiment except the third one.

So varying the nitrogen and carbon dioxide level in air could not contribute in his experiment.

<h2 />
Alenkasestr [34]2 years ago
6 0

Answer:

c

Explanation:

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iragen [17]

The Moment of Inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

I = I_{D} - I_{H} (1)

Where:

  • I_{D} - Moment of inertia of the Disk.
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Then, this formula is expanded as follows:

I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right) (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole (m):

\frac{m}{M} = \frac{R^{2}}{4\cdot R^{2}}

m = \frac{1}{2}\cdot M

And the resulting equation is:

I = \frac{1}{2}\cdot M\cdot R^{2} -\frac{1}{2}\cdot \left(\frac{1}{4}\cdot M \right) \cdot \left(\frac{1}{4}\cdot R^{2} \right)

I = \frac{1}{2} \cdot M\cdot R^{2} - \frac{1}{32}\cdot M\cdot R^{2}

I = \frac{15}{32}\cdot M\cdot R^{2}

The moment of inertia of the Disc is represented by I = \frac{15}{32}\cdot M\cdot R^{2}. (Correct answer: A)

Please see this question related to Moments of Inertia: brainly.com/question/15246709

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