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kaheart [24]
2 years ago
12

Malik formed a hypothesis that an increase in atmospheric oxygen levels by 10% would cause red-legged grasshoppers to grow large

r than normal. Suppose that Malik performs an experiment to test his hypothesis. Which of these actions would represent a scientific mistake in his experiment?
He experiments on live grasshoppers instead of preserved ones.
He focuses on red-legged grasshoppers instead of all kinds of grasshoppers.
He varies the nitrogen and carbon dioxide levels in the air from one trial to the next.
He conducts the experiment in a controlled lab setting with a lab partner.
He measures the mass and length of his specimens at the start of each trial.
Physics
2 answers:
worty [1.4K]2 years ago
8 0
<h2>Answer:</h2>

The option C is the correct answer.

Which is, "He varies the nitrogen and carbon dioxide levels in the air from one trial to the next".

<h3>Explanation:</h3>

The hypothesis of Malik was about the effect of increased oxygen level on the growth of the red-legged grasshoppers.

So the areas of his experiment should be the:

  • Grasshopper type.
  • High oxygen level.
  • Rate of growth of grasshopper.

So all the given options are relevant to his experiment except the third one.

So varying the nitrogen and carbon dioxide level in air could not contribute in his experiment.

<h2 />
Alenkasestr [34]2 years ago
6 0

Answer:

c

Explanation:

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gizmo_the_mogwai [7]

Answer:3.77 T/s

Explanation:

Given

Area of cross-section=3.7\times 3.7 cm^2=13.69 cm^2

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current (i)=0.04 A

emf induced=i\times R=0.04\times 8=0.32 V

emf induced e=NA\frac{\mathrm{d} B}{\mathrm{d} t}

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\frac{\mathrm{d} B}{\mathrm{d} t}=\frac{0.32\times 10^4}{848.78}=3.77 T/s

8 0
3 years ago
A 1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the cen
NeTakaya

Answer:

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

F_1 + F_2 = W

F_1 + F_2 = (1530\times 9.81)

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now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

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F_1(1.15) = F_2(2.70 - 1.15)

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F = 20240 N

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