Question

Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is switched off in 1.00 ms, inducing a 9.00 V emf in the other. What is their mutual inductance?

Answer 1

Answer:

Mutual inductance will be $M=1.8\times 10^{-3}Hennry$

Explanation:

We have given induced current $\Delta i=5A$

Time is given as $t=1ms=10^{-3}sec$

We have to find the mutual inductance between the coils

Induced emf is given as e = 9 volt

We know that induced emf is given by

$e=M\frac{\Delta i}{\Delta t}$

$9=M\times \frac{5}{10^{-3}}$

$M=1.8\times 10^{-3}Hennry$