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AfilCa [17]
3 years ago
7

Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is sw

itched off in 1.00 ms, inducing a 9.00 V emf in the other. What is their mutual inductance?
Physics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

Mutual inductance will be M=1.8\times 10^{-3}Hennry

Explanation:

We have given induced current \Delta i=5A

Time is given as t=1ms=10^{-3}sec

We have to find the mutual inductance between the coils

Induced emf is given as e = 9 volt

We know that induced emf is given by

e=M\frac{\Delta i}{\Delta t}

9=M\times \frac{5}{10^{-3}}

M=1.8\times 10^{-3}Hennry

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Answer : The value of q\text{ and }\Delta U is 286.2 J and 286.2 J respectively.

Explanation : Given,

Moles of sample = 0.877 mol

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First we have to calculate the heat absorbed by the system.

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q=n\times c_v\times \Delta T

where,

q = heat absorbed by the system = ?

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c_v = heat capacity at constant volume of N_2 (diatomic molecule) = \frac{5}{2}R

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Now put all the given value in the above formula, we get:

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\Delta U=q+w

As we know that, work done is zero at constant volume. So,

\Delta U=q=286.2J

Therefore, the value of q\text{ and }\Delta U is 286.2 J and 286.2 J respectively.

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