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AfilCa [17]
3 years ago
7

Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is sw

itched off in 1.00 ms, inducing a 9.00 V emf in the other. What is their mutual inductance?
Physics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

Mutual inductance will be M=1.8\times 10^{-3}Hennry

Explanation:

We have given induced current \Delta i=5A

Time is given as t=1ms=10^{-3}sec

We have to find the mutual inductance between the coils

Induced emf is given as e = 9 volt

We know that induced emf is given by

e=M\frac{\Delta i}{\Delta t}

9=M\times \frac{5}{10^{-3}}

M=1.8\times 10^{-3}Hennry

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<u>Explanation:</u>

Given:

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Total kinetic energy is E = \frac{1}{2} I_1w_0^2 + \frac{1}{2}I_2w_0^2 = \frac{1}{2} w_0^2(m_1x^2 + m_2(L-x)^2)

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Answer:

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