This is beacuse it is caused by light scattering of light in the atmosphere. When the moon rises blue light is caused and scattered also caused by earth's atmosphere and it is black on the moon as there is no lunar atmosphere , so no light scattering.
Answer:
R1 = 5.13 Ω
Explanation:
From Ohm's law,
V = IR............... Equation 1
Where V = Voltage, I = current, R = resistance.
From the question,
I = 2 A, R = R1
Substitute into equation 1
V = 2R1................ Equation 2
When a resistance of 2.2Ω is added in series with R1,
assuming the voltage source remain constant
R = 2.2+R1, and I = 1.4 A
V = 1.4(2.2+R1)................. Equation 3
Substitute the value of V into equation 3
2R1 = 1.4(2.2+R1)
2R1 = 3.08+1.4R1
2R1-1.4R1 = 3.08
0.6R1 = 3.08
R1 = 3.08/0.6
R1 = 5.13 Ω
There the potential difference is -0. 553 keQ/R.
What is Electric potential ?
The amount of labor required to convey a unit of electric charge from a reference point to a given place in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential).
Electric potential at point 0,
V1 = ke Q/R
Electric potential at x= 2R
V2= keQ/ root5. R
Therefore potential difference is
dV = V2 - V1
Putting the values we get ,
dV = -0. 553 keQ/R
To learn more about electric potential click on the link below:
brainly.com/question/23980243
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You just need the energy of turning of water in to steam. Water is a little funny because once water gets to 100 degrees C, it stops changing in temperature whilst it all turns to steam. The amount of energy required to turn 1 gram of water into steam is 2257 Joules. We call this the latent heat of vaporisation. So to turn 74.6 grams of water to steam, you would need:
2257J/gram x 74.6g = 168,372.2 J = 168.4 kJ
(<span></span><em>latent heat of vaporisation: 2257 J/gram</em>)
