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Komok [63]
3 years ago
14

A teacher makes the following statement.

Chemistry
2 answers:
ale4655 [162]3 years ago
8 0

Answer:

distillation of a mixture

Explanation:

Nat2105 [25]3 years ago
3 0

Answer:

A.) Distillation of mixture.

Explanation:

edge 2021

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Consider the reaction of glucose with oxygen: C6H12O6(s) + 6O2(g) Right arrow. 6CO2(g) + 6H2O(l)
lidiya [134]

Answer:

Subtract the sum of the heats of formation of the reactants from that of the products to determine delta H: delta H = –110.53 kJ/mol – (–285.83 kJ/mol) = 175.3 kJ.

Explanation:

Step 1: Set Up the Equation. Arrange your given ΔHf and ΔH values according to the following equation: ΔH = ΔHf (products) - ΔHf (reactants). ...

Step 2: Solve the Equation. Solve your equation for ΔHf. ...

Step 3: Validate the Sign. Adjust your ΔHf value's sign depending on whether it is for a product or a reactant.

3 0
3 years ago
A car is held motionless off the ground by a hovering helicopter. If the car's mass is 1500kg, what is the force on the car due
bixtya [17]

<span>Force of the helicopter is equivalent to weight for this case. </span>Weight is calculated by multiplying the mass of the object and the acceleration. For this case, the acceleration would be the acceleration due to gravity which is equal to 9.81 m/s^2. We calculate as follows:<span>

W = mg 
<span>W = 1500 kg ( 9.81 m/s^2 )</span></span>

<span><span>W = 14715 N </span></span>

6 0
3 years ago
Read 2 more answers
HELP LAST QUESTION WILL MAKE BRAINLIEST
Alenkasestr [34]

Answer:

I think it is C.)????

4 0
3 years ago
How many molecules are there in 223 grams of Na2SO4?
Harlamova29_29 [7]
<h3><u>Answer;</u></h3>

= 9.45 × 10^23 molecules

<h3><u>Explanation; </u></h3>

The molar mass of Na2SO4 = 142.04 g/mol

Number of moles = mass/molar mass

                             = 223/142.04

                             =  1.57 moles

But;

1 mole = 6.02 × 10^23 molecules

Therefore;

1.57 moles = ?

= 1.57 × 6.02 × 10^23 molecules

<u>= 9.45 × 10^23 molecules </u>

8 0
3 years ago
Suppose that you add 26.7 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the adde
nadya68 [22]

Answer: The molar mass of the unknown compound is 200 g/mol

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=2.74^0C = Depression in freezing point

i= vant hoff factor = 1 (for molecular compound)

K_f = freezing point constant = 5.12^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (benzene)= 0.250 kg  

Molar mass of solute = M g/mol

Mass of solute  = 26.7 g

2.74^0C=1\times 5.12\times \frac{26.7g}{Mg/mol\times 0.250kg}

M=200g/mol

Thus the molar mass of the unknown compound is 200 g/mol

4 0
4 years ago
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