2 NaClO3→ 2 NaCl + 3 O2<br><br> How many moles of O2 are produced when 40g of NaCl are formed?

Please help! This is for the 9.06 Acid Neutralization Lab! Due today!

Volgvan

hi there bestie [i think its 3]

5 0

2 years ago

What can form as a result of a chemical reaction?

cestrela7 [59]

Answer is: new substance.

For example, synthesis chemical reaction: Ba + F₂ → BaF₂.

Synthesis reaction is a type of reaction in which multiple reactants combine to form a single product.

New substance, barium fluoride is formed, with different chemical and ohysical properties than reactants (barium and fluorine).

In barium fluoride, barium has oxidation number +2 and fluorine has oxidation number -1, so compound has neutral charge.

4 0

3 years ago

Read 2 more answers

How many moles of TNT would be detonated if you used 539.88 grams of TNT? The structure of TNT is C7H5N3O6. Round your answer to

Kruka [31]

Answer:

Moles of TNT = 2.38 moles

Explanation:

First , calculate the molar mass of the compound TNT

The formula is : C7H5N3O6

How to calculate molar mass?

Molar mass : It is the mass of substance in grams which is present in 1 mole of the compound.It is calculated by:

Molar mass = Number of atoms x the atomic mass of the element

Atomic mass of the elements are given below :

C = 12.0107

H = 1.0079

N = 14.0067

O = 15.9994

Molar mass of C7H5N3O6 =

= (7 x C) + (5 x H) + (3 x N) + (6 x O)

= 7(12.0107) +5(1.0079) + 3(14.0067) + 6(15.9994)

Molar mass = 227 .13 gram/mole

Mole are calculated using the formula:

$Moles =\frac{given\ mass}{Molar\ mass}$

Given mass = 539.88 grams

Molar mass = 227.13 g/mole

$Moles =\frac{539.88}{227.13}$

= 2.3769

Moles = 2.38 moles

5 0

3 years ago

In this molecule, what's the formal charge on the central O atom?

olga_2 [115]

The answer you are looking for is C

3 0

3 years ago

Read 2 more answers

The hydrogen chloride (HCl) molecule has an internuclear separation of 127 pm (picometers). Assume the atomic isotopes that make

natta225 [31]

Answer:

the energy of the third excited rotational state $\mathbf{E_3 = 16.041 \ meV}$

Explanation:

Given that :

hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm

Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.

Thus; the reduced mass μ = $\dfrac{m_1 \times m_2}{m_1 + m_2}$

μ = $\dfrac{1 \times 35}{1 + 35}$

μ = $\dfrac{35}{36}$

∵ 1 μ = 1.66 × 10⁻²⁷ kg

μ = $\\ \\ \dfrac{35}{36} \times 1.66 \times 10^{-27} \ \ kg$

μ = 1.6139 × 10⁻²⁷ kg

$r_o = 127 \ pm = 127*10^{-12} \ m$

The rotational level Energy can be expressed by the equation:

$E_J = \dfrac{h^2}{8 \pi^2 I } \times J ( J +1)$

where ;

J = 3 ( i.e third excited state) &

$I = \mu r^2_o$

$E_J= \dfrac{h^2}{8 \pi \mu r^ 2 \mur_o } \times J ( J +1)$

$E_3 = \dfrac{(6.63 \times 10^{-34})^2}{8 \times \pi ^2 \times 1.6139 \times 10^{-27} \times( 127 \times 10^{-12}) ^ 2 } \times 3 ( 3 +1)$

$E_3= 2.5665 \times 10^{-21} \ J$

We know that :

1 J = $\dfrac{1}{1.6 \times 10^{-19}}eV$

$E_3= \dfrac{2.5665 \times 10^{-21} }{1.6 \times 10^{-19}}eV$

$E_3 = 16.041 \times 10 ^{-3} \ eV$

$\mathbf{E_3 = 16.041 \ meV}$

8 0

2 years ago

2 NaClO3→ 2 NaCl + 3 O2 How many moles of O2 are produced when 40g of NaCl are formed?