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Lesechka [4]
3 years ago
15

A student assistant is cleaning up after a chemistry laboratory exercise and finds three one-liter bottles containing alcohol so

lutions. The first bottle is one-half full with a 20% alcohol solution, the second bottle is one-fifth full with a 30% alcohol solution, and the third bottle is one-tenth full with a 50% alcohol solution. The student pours the contents of all three bottles into an empty one-liter bottle. What is the approximate alcohol content of this mixed solution
Chemistry
1 answer:
Svetllana [295]3 years ago
3 0

The approximate alcohol content is 210 ml.

Explanation:

It can be deduced from the question that each bottle is of 1000ml or 1 litre.

The first bottle is one half full means it has 500 ml of solution and it has 20% alcohol in it. So volume of alcohol in the solution is

20/100*500

=100 ml

The first bottle is one fifth full, so the volume of mixture is 1/5th of 1000ml

so it is 200ml having 30% alcohol

30/100*200

= 60 ml

The third bottle is one tenth full so its volume is 1/10*1000

100 ml.  having 50% of alcohol

50/100*100

50 ml.

The alcohol content obtained from all these 3 litres is:

100+60+50

= 210 ml of alchohol is obtained from 800 ml of mixture.

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Composition of Dry AirGas Percent by Volume (%)Nitrogen (N2) 78Oxygen (O2) 21Argon (Ar) 0.9Carbon dioxide (CO2) 0.04 What volume
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Answer:

40.95 L

Explanation:

We'll begin by calculating the number of mole in 12.3 g of O₂. This can be obtained as follow:

Mass of O₂ = 12.3 g

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Mole of O₂ =?

Mole = mass / Molar mass

Mole of O₂ = 12.3 / 32

Mole of O₂ = 0.384 mole

Next, we shall determine the volume occupied by 0.384 mole of O₂. This can be obtained as follow:

Number of mole (n) of O₂ = 0.384 mole

Pressure (P) = 1 atm

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Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of O₂ =?

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Thus, the volume of O₂ is 8.6 L

Finally, we shall determine the volume of air that contains 8.6 L of O₂. This can be obtained as follow:

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Percentage of O₂ = Vol of O₂ / Vol of air × 100

21% = 8.6 / Vol of air

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Cross multiply

21 × Vol of air = 100 × 8.6

21 × Vol of air = 860

Divide both side by 21

Volume of air = 860 / 21

Volume of air = 40.95 L

Therefore, the volume of air is 40.95 L.

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