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MaRussiya [10]
3 years ago
15

A vertical tube 1.34 m long is open at the top.It is filled with 44.2 cm of water.If the speed of sound is 344 m/s, what willthe

fundamental resonant frequency be
Physics
1 answer:
tester [92]3 years ago
5 0

Answer:

the fundamental resonant frequency is 95.76 Hz

Explanation:

The computation of the fundamental resonant frequency be is given below:

= 1.34 m - 0.442 m

= 0.898 m

Now

L = \frac{\lambda}{4} \\\\\lambda = 4L

Now the fundamental resonant frequency is

f = \frac{V}{\lambda} \\\\= \frac{V}{4L}\\\\= \frac{344}{4\times 0.898}

= 95.76 Hz

hence, the fundamental resonant frequency is 95.76 Hz

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Answer:

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The momentum of an object is equal to its mass times its velocity.

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1000\,v_0 = 995\,(v_0 + \Delta v) + 5\,(v_0 - 500).

Note that 1000\, v_0 appears on both sides of the equation. These two terms could hence be eliminated.

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Answer:

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