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3 years ago

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You are an astronomer on planet Nearth, which orbits a distant star. It has recently been accepted that Nearth is spherical in s

hape, though no one knows its size. One day, while studying in the library of Alectown, you learn that on the equinox your sun is directly overhead in the city of Nyene, located 1200 kilometers due north of you. On the equinox, you go outside in Alectown and observe that the altitude of your sun is 79 ∘.

2 answers:

MatroZZZ [7]3 years ago

8 0

This is how you should do it:

Use Eratosthenes formula, and replace it with your numbers like this:

(360/11) x (1200 km) = 39,273 km

spayn [35]3 years ago

4 0

You know now that 1200 km is 11° of latitude on the planet. So its circumference is roughly approximately around something like about

(360/11) • (1200 km) = 39,273 km

If it was good enough for Eratosthenes, then we can't complain.

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A wave has a velocity of 24 m/s and a period of 3.0 s. Calculate the wavelength of the wave.

Katyanochek1 [597]

Velocity (unit:m/s) of the wave is given with the formula:

v=f∧,

where f is the frequency which tells us how many waves are passing a point per second (unit: Hz) and ∧ is the wavelength, which tells us the length of those waves in metres (unit:m)

f=1/T , where T is the period of the wave.

In our case: f=1/3

∧=v/f=24m/s/1/3=24*3=72m

5 0

3 years ago

A package of mass m is released from rest at a warehouse loading dock and slides down a 3.0-m-high frictionless chute to a waiti

LuckyWell [14K]

Answer:

The speed of the package of mass m right before the collision $= 7.668\ ms^-1$

Their common speed after the collision $= 2.56\ ms^-1$

Height achieved by the package of mass m when it rebounds $= 0.33\ m$

Explanation:

Have a look to the diagrams attached below.

a.To find the speed of the package of mass m right before collision we have to use law of conservation of energy.

$K_{initial} + U_{initial} = K_{final}+U_{final}$

where $K$ is Kinetic energy and $U$ is Potential energy.

$K= \frac{mv^2}{2}$ and $U= mgh$

Considering the fact $K_{initial} = 0\ and U_{final} =0$ we will plug out he values of the given terms.

So $V_{1}{(initial)} =\sqrt{2gh} = \sqrt{2\times9.8\times3} = 7.668\ ms^-1$

Keypoints:

Sum of energies and momentum are conserved in all collisions.
Sum of KE and PE is also known as Mechanical energy.
Only KE is conserved for elastic collision.
for elastic collison we have $e=1$ that is co-efficient of restitution.

<u>KE = Kinetic Energy and PE = Potential Energy</u>

b.Now when the package stick together there momentum is conserved.

Using law of conservation of momentum.

$m_1V_1(i) = (m_1+m_2)V_f$ where $V_1{i} =7.668\ ms^-1$ .

Plugging the values we have

$m\times 7.668 = (3m)\times V_{f}$

Cancelling m from both sides and dividing 3 on both sides.

$V_f = 2.56\ ms^-1$

Law of conservation of energy will be followed over here.

c.Now the collision is perfectly elastic $e=1$

We have to find the value of $V_{f}$ for m mass.

As here $V_{f}=-2.56\ ms^-1$ we can use that if both are moving in right ward with $2.56$ then there is a $-2.56$ velocity when they have to move leftward.

The best option is to use the formulas given in third slide to calculate final velocity of object $1$ .

So

$V_{1f} = \frac{m_1-m_2}{m_1+m_2} \times V_{1i}= \frac{m-2m}{3m} \times7.668=\frac{-7.668}{3} = -2.56\ ms^-1$

Now using law of conservation of energy.

$K_{initial} + U_{initial} = K_{final}+U_{final}$

$\frac{m\times V(f1)^2}{2} + 0 = 0 +mgh$

$\frac{v(f1)^2}{2g} = h$

$h= \frac{(-2.56)^2}{9.8\times 3} =0.33\ m$

The linear momentum is conserved before and after this perfectly elastic collision.

So for part a we have the speed $=7.668\ ms^-1$ for part b we have their common speed $=2.56\ ms^-1$ and for part c we have the rebound height $=0.33\ m$ .

3 0

3 years ago

The force that resists moving one object against another is _____. friction push energy work

Novosadov [1.4K]

The answer is A. Friction.

Friction is the resisting force between two objects that move against one another.

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

А geostationary satellite moves in an orbit of radius 6300km. Calculate the speed with which it moves in the orbit [π=22÷7]

azamat

Answer:

15.3 m/s

Explanation:

Radius of orbit= 6400+6300 = 12700 km

Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m

Now,

Speed= Distance / Time

= 79796.45*10^3/(24*60*3600)

= 15.3 m/s

4 0

2 years ago

Use the concepts on which maxwell’s equations are based to explain why a compass needle is deflected when the compass is brought

miv72 [106K]

A conductor that is conducting current generates a magnetic field everywhere around it. This magnetic field exerts force on the compass's magnetic needle, causing the needle to deviate.

Definition of Maxwell's rule

A current-conducting conductor creates a magnetic field everywhere around it. The magnetic needle of the compass experiences force from this magnetic field, which causes the needle to veer.

Equation for deflection

We have so far established that the total flux of electric field out of a closed surface is just the total enclosed charge multiplied by 1/ε0, ∫→E⋅d→A=q/ε0. This is Maxwell's first equation. It represents completely covering the surface with a large number of tiny patches having areas d→A.

To learn more about magnetic field refer : brainly.com/question/24761394

#SPJ4

7 0

1 year ago