A= (99x1+0,8x2+0,2x3)÷100%=1,012
1,012≈1
Answer:
I don't know because I don't know about chemistry
Answer:
155 A
Explanation:
Given data
- Transported charge (Q): 93.0 Coulomb
- Elapsed time (t): 601 ms = 0.601 seconds
We can determine the magnitude of the electric current (I) using the following expression.
I = Q / t
I = 93.0 C / 0.601 s
I = 155 C/s
I = 155 A
The magnitude of the electric current is 155 Ampere.