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Mazyrski [523]
3 years ago
14

If 2.0 mol of Zn is mixed with 3.0 mol of HCl, which reactant will be limiting?

Chemistry
1 answer:
Soloha48 [4]3 years ago
8 0

The following Balanced Reaction will take place:

Zn + 2HCl → ZnCl₂ + H₂

In the question, we have 2 moles of Zinc and 3 moles of HCl for this reaction

<u>Amount of HCl required to completely react with 2 moles of Zn:</u>

Since we need 2 moles of HCl for every mole of Zn, we will need 2(2) = 4 moles of HCl for every 2 moles of Zn

<u>Identifying the Limiting Reagent:</u>

But we are only given 3 moles of HCl where we need 4 moles to completely react.

So, since HCl is in less amount, it is the Limiting Reagent

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telo118 [61]

The pH scale was given by Sorensen to quanitatively define strength of an acid and base

the pH scale extends from 0 to 14

For acids

The pH should be less than 7 [always]

For base

The pH should be more than 7 [always]

The pH seven is of neutral solution

pH = -log[H+]

Thus lower the pH higher the concentration of hydronium ion or protons produced by an acid

thus for the given pH scale interval [0-3] it represents strong acid [Which will give high concentration of protons on dissociation]

4 0
3 years ago
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What the wavelength of a light whose frequency is 7.00 x 10^16 Hz
nata0808 [166]
V = c \Lambda
7 x 10^16 = 3 x 10^8 / lambda
lambda = 42.85
7 0
4 years ago
Is anyone good at chemistry if so can someone help me please ?<br><br> (NO LINKS)
Daniel [21]

The reactions are a bit poorly written. While it's true that aqueous H₂CO₃ is produced in this neutralization reaction, the H₂CO₃ rapidly decomposes to yield CO₂(g) and H₂O(l). Writing the product as H₂CO₃(aq) in the net ionic equation is unnecessarily confusing since it portrays the substance as nonionizing yet water-soluble.

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7 0
3 years ago
The combustion of 1.685 g of propanol (C3H7OH) increases the temperature of a bomb calorimeter from 298.00 K to 302.16 K. The he
AfilCa [17]

Answer:

ΔH =  - 2020.57 kJ/mol

Explanation:

Given that :

mass of propanol = 1.685 g

the molar molar mass = 60 g/mol

Thus; the number of  moles = mass/molar mass

= 1.685 g/60 g/mol

= 0.028 g/mol

However ;

ΔH = heat capacity C × Δ T

Given that:

The temperature increases from  298.00 K to 302.16 K.

Then ;

Δ T = 302.16 K - 298.00 K

Δ T = 4.16 K

heat capacity C = 13.60 kJ/K

∴

ΔH = 13.60 kJ/K × 4.16 K

ΔH =  56.576 kJ

The equation of the given reaction can be represented as :

C_3H_7OH_{(l)}+\dfrac{3}{2}O_{2(g)}  \to 3CO_{2(g)} +4H_2O_{(l)}

Thus for 0.028 mol of heat liberated; ΔH =  56.576 kJ

For 1 mole of heat liberated now:

ΔH =  56.576 kJ/0.028 mol

ΔH =  2020.57 kJ/mol

SInce , Heat is liberated, the reaction undergoes an exothermic reaction thus;

ΔH =  - 2020.57 kJ/mol

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Answer:

the answer is convection

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