By using distance formula (which is attached below), you can solve this problem:
√(x2-x1)^2+(y2-y1)^2
(5, -1) and (5, 3)
√(5-5)^2+(3-(-1))^2
√0^2+4^2
√0+16
√16
4
The distance between the two points is 4.
The greatest common factor (GCF) of 8 and 14 is 2
Answer:solve for x
-3x+5y=-15
Add -5y to both sides
-3x+5y+-5y=-15+-5y
-3x=-5y-15
Divide both sides by -3
-3x/-3=-5y-15/-3
x= 5/3 y +5
I hope that's help!
Step-by-step explanation: plz give brainlist
Hello,
2x^3+14x^2+6x+42=2x^2(x+7)+6(x+7)
=(x+7)(2x²+6)
=2(x+7)(x²+3) in IR.
or In C 2(x+7)(x-i√3)(x+i√3)
