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aev [14]
3 years ago
15

When most fuels burn, water and carbon dioxide are the two main products. Why can´t you say that water and carbon dioxide are pr

oducts of all combustion reactions
Chemistry
2 answers:
STatiana [176]3 years ago
7 0
That is only the combustion of a hydrocarbon. Rust is a combustion reaction because oxygen is added.

Fe(s) + O2(g) => FeO2(s)
Keith_Richards [23]3 years ago
7 0

<u>Answer:</u> Because some of the processes are also known as incomplete combustion.

<u>Explanation:</u>

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.  The chemical equation for this reaction follows:

\text{hydrocarbon}+O_2\rightarrow CO_2+H_2O

If supply of oxygen gas is limited, it is known as incomplete combustion and carbon monoxide gas is also produced as a product. The chemical equation for this reaction follows:

\text{hydrocarbon}+O_2\text{(limited)}\rightarrow CO+CO_2+H_2O

Thus, we cannot say that all the combustion reactions produce carbon dioxide and water as products because it depends on the supply of oxygen gas.

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Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin
Gwar [14]

The molarity of the solution is the moles dissolved per liter. The volume of 0.8 M citric acid solution will be 74.16 mL.

<h3>What is molarity?</h3>

Molarity of the solution is the concentration that is given by the moles of the solute that are dissolved to make the solution in liters.

The chemical reaction between baking soda and citric acid is shown as:

C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Given,

Molarity = 0.8 M

Mass of baking soda = 15 grams

The molar mass of baking soda = 84.007 g/mol

Moles of baking soda = 15 ÷ 84.007 = 0.178 moles

From the reaction, it can be said that 3 moles of baking soda are required to react with 1 mole of citric acid. So, 0.178 moles will need, 0.059 moles.

The volume of citric caid needed is calculated as:

M = moles ÷ volume

Volume (L) = 0.059 ÷ 0.8

= 0.07416 L

Volume is converted into mL as:

1 L = 1000 mL

0.07416 L = 74.16 mL

Therefore, 74.16 mL is the volume of citric acid needed.

Learn more about molarity here:

brainly.com/question/7145257

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5 0
2 years ago
What is the percent composition of hydrogen in glucose
Ulleksa [173]

Answer:

<h2>67%</h2>

Explanation:

<h2>Thus the % composition of glucose by mass is carbon 40.0 % oxygen 53.3 % hydrogen 6.7 % in this way, the % composition by mass of any compound can be calculated provided that is formed is known. </h2>
6 0
3 years ago
Which statement about the surface of the moon is true?
Anna [14]

Answer:

There is no air, wind, liquid water or life on the moons surface.

Explanation:

8 0
3 years ago
Which of the following would be more likely to conduct electrons? Strontium or Iodine? Defend your choice.
Alchen [17]
Strontium because it is a metal
6 0
3 years ago
What is the ph of a 0.25 m solution of c6h5nh2 given that its kb is 1.8 x 10-6?
IrinaK [193]

The pH a 0.25 m solution of C₆H₅NH₂ is equal to 3.13.

<h3>How do we calculate pH of weak base?</h3>

pH of the weak base will be calculate by using the Henderson Hasselbalch equation as:

pH = pKb + log([HB⁺]/[B])

pKb = -log(1.8×10⁻⁶) = 5.7

Chemical reaction for C₆H₅NH₂ is:

                          C₆H₅NH₂ + H₂O → C₆H₅NH₃⁺ + OH⁻

Initial:                     0.25                           0            0

Change:                    -x                             x             x

Equilibrium:        0.25-x                           x             x

Base dissociation constant will be calculated as:
Kb = [C₆H₅NH₃⁺][OH⁻] / [C₆H₅NH₂]

Kb = x² / 0.25 - x

x is very small as compared to 0.25, so we neglect x from that term and by putting value of Kb, then the equation becomes:

1.8×10⁻⁶ = x² / 0.25

x² = (1.8×10⁻⁶)(0.25)

x = 0.67×10⁻³ M = [C₆H₅NH₃⁺]

On putting all these values on the above equation of pH, we get

pH = 5.7 + log(0.67×10⁻³/0.25)

pH = 3.13

Hence pH of the solution is 3.13.

To know more about Henderson Hasselbalch equation, visit the below link:
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5 0
2 years ago
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