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Ostrovityanka [42]
2 years ago
9

When an -OH group joins a hydrocarbon, an alcohol is formed. true or falsse

Chemistry
1 answer:
Nezavi [6.7K]2 years ago
8 0
It usually disobeys pretty quick
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When a sodium atom becomes an ion the size of the atom?
jeyben [28]
The size of atom reduces

Electronic configuration of sodium -
2,8,1

In order to become stable it loses one electron and becomes positive ion.
It's size reduces.
3 0
3 years ago
How much salt (NaCl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/L of salt
denis23 [38]

Answer:

129,600kg/day

Explanation:

The river is flowing at 30.0

1 m³ is equivalent to 1000L

flowrate of river = 30*1000 =30,000L/s

Convert L/s to litre per day by multiplying by 24*60*60

flowrate of river = 30,000 * 24*60*60 L/day

                    = 2,592,000,000L/day

if the river contains 50mg of salt  in 1L of solution

lets find how many mg of salt Y is contained in 2,592,000,000L/day

by cross multiplying we have

Y=\frac{2592000000*50}{1}

Y= 129,600,000,000 mg/day

convert this value to kg/day by dividing by 1 million

Y= 129,600,000,000/1000000

Y= 129,600kg/day

3 0
2 years ago
What are m and n in the rate law equation? Rate = k[A]^m[B]^n A. They are the coefficients obtained from the equation. B. They a
Sav [38]
The answer is A. The m and n are the coefficients obtained from the equation. And important thing is that the equation need to be balanced before using its coefficients.
5 0
2 years ago
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On a scale 1-10 how pretty am I?
Readme [11.4K]

Answer:

10

Explanation:

ur pefrct no matter the inside or outside

5 0
2 years ago
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Timed PLS help
Bezzdna [24]

Answer:

19.5g is the theoretical yield of alum

Explanation:

Based on the balanced reaction, 4 moles of sulfuric acid produce 2 moles of alum. To solve this question we need to find the moles of H2SO4. With these moles we can find the moles of alum and its mass assuming all sulfuric acid reacts producing alum.

<em>Moles Sulfuric Acid:</em>

8.3mL = 0.0083L * (9.9mol/L) = 0.08217 moles sulfuric acid

<em>Moles Alum:</em>

0.08217 moles sulfuric acid * (2mol KAl(SO4)2•12H2O / 4mol H2SO4) =

0.041085 moles KAl(SO4)2•12H2O

<em>Mass Alum -Molar mass: 474.3884 g/mol-</em>

0.041085 moles KAl(SO4)2•12H2O * (474.3884 g/mol) =

<h3>19.5g is the theoretical yield of alum</h3>
3 0
2 years ago
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