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Feliz [49]
3 years ago
14

The average distance between the Sun and a certain planet is approximately 2.3 x 1014 inches. Which of the following is closest

to the average distance between the Sun and the planet, in kilometers? (1 kilometer is approximately 3.9 x 104inches.) (A) 7.1 x 10^8(B) 5.9 x 10^9(C) 1.6 x 10^10(D) 1.6 x 10^11(E) 5.9 x 10^11
Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:

B. 5.9 X 10^9

Explanation:

For this question, we assume the following:

•2.3 x 1014 inches is actually 2.3 x 10^14 inches.

•3.9 x 104inches is actually 3.9 x 10^4inches

We now calculate thus;

The average distance in km would be 2.3 x 10^14/3.9 x 10^4

= 0.59 X 10^10.

Therefore, we have;

5.9 X 10^9km.

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A car accelerates from rest at 3.00 m/second squared What is the velocity after 5 secs ? What is the displacement after 5 second
andrey2020 [161]

Explanation:

after 5 seconds, the velocity is (5s)(3m/s²) = 15m/s

The displacement after 5s is

x=vo + (1/2)at²

x = 0 + (1/2)(3m/s²)(5s)(5s)

x= 37.5 m

3 0
3 years ago
f your risk-aversion coefficient is A = 4 and you believe that the entire 1926–2015 period is representative of future expected
siniylev [52]

Answer:

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

Explanation:

As the complete question is not given here ,the table of data is missing which is as attached herewith.

From the maximized equation of the utility function it is evident that

Weight=\frac{E_M-r_f}{A\sigma_M^2}

For the equity, here as

  • Weight is percentage of the equity which is to be calculated
  • {E_M-r_f} is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
  • A is the risk aversion factor which is given as 4.
  • \sigma_M is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59

By substituting values.

Weight=\frac{E_M-r_f}{A\sigma_M^2}\\Weight=\frac{8.30\%}{4(20.59\%)^2}\\Weight=0.4894 =48.94\%

So the weight of equity is 48.94%.

Now the weight of T bills is given as

Weight_{T-Bills}=1-Weight_{equity}\\Weight_{T-Bills}=1-0.4894\\Weight_{T-Bills}=0.5105=51.05\%\\

So  the weight of T-bills is 51.05%.

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

7 0
3 years ago
The Earth orbits around the sun because the gravitational force that the sun
kotykmax [81]
<h3>Question -:</h3>

The Earth orbits around the sun because the gravitational force that the sun

exerts on the Earth:

O A. causes Earth's acceleration toward the sun.

O B. is very small because the sun is so far from the Earth.

O c. is smaller than the force the Earth exerts on the sun.

O D. pushes the Earth away from the sun.

<h3>Answer -:</h3>

O A. causes Earth's acceleration toward the sun.

<em>I </em><em>hope </em><em>this</em><em> </em><em>helps</em><em>,</em><em> </em><em>have </em><em>a </em><em>nice </em><em>time </em><em>ahead!</em>

5 0
2 years ago
If the faster stone takes 12.0 s to return to the ground, how long will it take the slower stone to return?
iren [92.7K]
Same speed, because mass is neglected. The things that affect the speed are the distance and speed of the rock.
5 0
3 years ago
I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Ulleksa [173]

Answer:

<em>B. 68.6m</em>

Explanation:

<u>Free Fall Motion </u>

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

\displaystyle y=\frac{gt^2}{2}

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

\displaystyle y=\frac{(9.8)(3.474)^2}{2}

\displaystyle y=68.54\ m

The closest correct option is

B. 68.6m

5 0
3 years ago
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