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3 years ago

An 8 N force accelerates an object at a rate of 2.5 m/s what Is the mass of the object

Physics

2 answers:

shtirl [24]3 years ago

8 0

Answer: 3.2 kilograms

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Work Shown:

F = 8 newtons = force applied
m = unknown mass in kilograms
a = 2.5 m/s^2 = acceleration

Apply Newton's Second Law of Motion

F = m*a

8 = m*2.5

2.5m = 8

m = 8/2.5

m = 3.2

The mass is 3.2 kilograms

DaniilM [7]3 years ago

6 0

Answer:

16N

Explanation:

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A transformer connected to a 110–(V) (rms) ac line is to supply 10.0 (V) (rms) to a portable electronic device. The load resista

spayn [35]

Answer:

Explanation:

a ) V( primary ) = 100 V

V( secondary ) = 10 V

No of turns ( secondary ) / No of turns ( primary ) = 10 / 100

= 1 / 10

b ) current in secondary

= volt ( secondary ) / resistance

= 10 /6 = 1.67 A

c )

Average power to secondary

= V ( secondary ) x current ( secondary )

= 10 x 10 / 6

= 16.67 W

d )

Power in primary = power in secondary = 16.67 W

e ) current drawn by ac line ( primary )

Volt ( primary ) x current ( primary ) = power in primary

= 16.67

current ( primary )

= 16.67 / 100

= 0.167 A

5 0

3 years ago

If part of an electric circuit dissipates energy at 6 W when it draws a current of 3 A, what voltage is impressed across it?

Lena [83]

Answer:2 volts

Explanation:

Power=current x voltage

6=3 x voltage

Divide both sides by 3

6/3=(3 x voltage)/3

2=voltage

Voltage=2volts

5 0

3 years ago

In a crash test, a 1000 kg automobile moving at 10 m/s crashes into a brick wall. How much energy goes into demolishing and warm

marishachu [46]

Answer:

Explanation:

Given

mass of automobile $m=1000\ kg$

velocity of automobile $v=10\ m/s$

If the automobile crashes into the brick wall then it's kinetic energy is converted into thermal and demolishing energy to wall.

Car completely stops as it crashes into the wall so Energy converted into demolition and thermal energy

$E=\frac{1}{2}mv^2$

$E=\frac{1}{2}\times 1000\times (10)^2$

$E=50\ kJ$

8 0

3 years ago

To practice Problem-Solving Strategy 27.1: Magnetic Forces. A particle with mass 1.81×10−3 kgkg and a charge of 1.22×10−8 CC has

Roman55 [17]

Answer:

The magnitude of the acceleration is $a = 0.33 m/s^2$

The direction is $- \r k$ i.e the negative direction of the z-axis

Explanation:

From the question we are that

The mass of the particle $m = 1.8*10^{-3} kg$

The charge on the particle is $q = 1.22*10^{-8}C$

The velocity is $\= v = (3.0*10^4 m/s ) j$

The the magnetic field is $\= B = (1.63T)\r i + (0.980T) \r j$

The charge experienced a force which is mathematically represented as

$F = q (\= v * \= B)$

Substituting value

$F = 1.22*10^{-8} (( 3*10^4 ) \r j \ \ X \ \ ( 1.63 \r i + 0.980 \r j )T)$

$= 1.22 *10^{-8} ((3*10^4 * 1.63)(\r j \ \ X \ \ \r i) + (3*10^4 * 0.980) (\r j \ \ X \ \ \r j))$

$= (-5.966*10^4 N) \r k$

Note :

$i \ \ X \ \ j = k \\\\j \ \ X \ \ k = i\\\\k \ \ X \ \ i = j\\\\j \ \ X \ \ i = -k \\\\k \ \ X \ \ j = -i\\\\i \ \ X \ \ k = - j\\$

Now force is also mathematically represented as

$F = ma$

Making a the subject

$a = \frac{F}{m}$

Substituting values

$a =\frac{(-5.966*10^4) \r k}{1.81*10^{-3}}$

$= (-0.33m/s^2)\r k$

$= 0.33m/s^2 * (- \r k)$

6 0

3 years ago

Which particles account for most of the mass of an atom?

BartSMP [9]

Protons and Neutrons account for most of an atoms mass

8 0

3 years ago