Explanation:
Given data
Inductance L=12*10^-³H
Capacitance C= 3.5*10^-6F
Resistance R= 3.3 Ohms
Voltage V=115v
Capacitive reactance Xc=?
inductive reactance Xl=?
Impedance Z=?
Phase angle =?
A. Resonance frequency
In RLC circuit resonance occurs when capacitive reactance equals inductive reactance
f=1/2pi √ LC
f=1/2*3.142 √ 12*10^-³*3.5*10^-6
f=1/6.284*0.0002
f=1/0.00125
f=800HZ
B. Find Irms at resonance.
Irms=R/V
Irms=3.3/115
Irms=0.028amp
Find the capacitive reactance XC in Ohms
Xc=1/2pi*f*C
Xc=1/2*3.142*800*3.5*10^-6
Xc=1/0.0176
Xc=56.8 ohms
To find the inductive reactance
Xl=2pifL
Xl=2*3.142*800*12*10^-3
Xl=60.3ohms
d) Find the impedance Z.
Z=√R²+(Xl-Xc)²
Z=√3.3²+(60.3-56.8)²
Z=√10.89+12.25
Z=√23.14
Z=4.8ohms
Phase angle =
Tan phi=Xc/R=56.8/3.3
Tan phi=17.2
Phi=tan-1 17.2
Phi= 1.51°
Explanation:
Given:
u = 20 m/s
a = 5 m/s^2
v = 30 m/s
t = ?
Use the first kinematic equation of motion:
v = u + at
t = (v - u)/a = 10/5 = 2 seconds
Answer:
The time taken by the brick to hit the ground, t = 0.84 s
Explanation:
Given that,
A brick falls from a height, h = 3.42 m
The initial velocity of the brick is zero.
Since the brick is under free-falling. The time equation of a free-falling body when the displacement is given is
t = 
where,
h - height from surface in meters
g - acceleration due to gravity
on substituting the values in the above equation,
t = 
= 0.84 s
Hence, time taken by the brick to hit the ground is t = 0.84 s
Answer:
As the number of turns in the coil increases, the strength of the electromagnet increases.
Explanation:
When current flows through a coil the coil behaves as an electromagnet. The strength of electromagnet depend the amount of current, no of turns of coil and the core of coil.
B=μ₀ N I
μ₀ = permeability of the core
N = Number of turns of the coil
I = Current flowing through the coil
Increasing the current and number of coils increase the strength of electromagnet.
Answer:
Explanation:
Mass of nails is 0.25kg
Mass of hammer 5.2kg
Speed of hammer is =52m/s
Then, Ben kinetic energy is given as
K.E= ½mv²
K.E= ½×5.2×52²
K.E= 7030.4J
Given that, two-fifth of kinetic energy is converted to internal energy
Internal energy (I.E) = 2/5 × K.E
Internal energy (I.E) = 2/5 × 7030.4
I.E=2812.16J.
Energy increase is total Kinetic energy - the internal energy
∆Et= K.E-I.E
∆Et= 7030.4 - 2812.16
∆Et= 4218.24J
