The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be C is 367.42 Hz.
A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.
The fundamental frequency in the tube is given by
where,
Since, T=37+273 K = 310 K
v = 331 m/s
Using this, we get:
Hence, the fundamental frequency is 367.42 Hz.
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Answer:
Value of electric field along the axis and equitorial axis and
respectively.
Explanation:
Given :
Distance between charges ,
Magnitude of charges ,
Dipole moment ,
Case A) (x,y) = (12.0 cm, 0 cm) :
Electric field of dipole in its axis ,
Putting all values and
We get ,
Case B) (x,y) = (0 cm, 12.0 cm) :
Electric field of dipole on equitorial axis ,
Putting all values and
We get ,
Hence , this is the required solution.
Answer:
Explanation:
Given data
Length of tube L=0.632 m
Speed of sound v=344 m/s
To find
Fundamental frequency f
Solution
The fundamental frequency of the tube can be given as: