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3 years ago

A boat goes 8 m/ due north against a current of 3m/s. what is the resultant velocity of the boat?

Physics

2 answers:

Mariana [72]3 years ago

5 0

5 its 5 5 its 5 5 its 5 5

tino4ka555 [31]3 years ago

4 0

If Boat is going in opposite direction to current, then their resultant velocity will be

Vab = Va - Vb

Vab = 8 - 3 = 5

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Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d

Step2247 [10]

Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that $F = k \frac{Q_1Q_2}{d^2}$ so if we double the charge on $Q_1$ and double the distance to $(2d)$ we plug these into the equation to find

<span> $F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}$ </span>

So we see the new force is exactly 1/2 of the old force so your answer should be $\frac{1}{2}F$ if I can remember my physics correctly.

9 0

4 years ago

Read 2 more answers

75000×(151÷100)².WHAT IS ITS VALUE ???

Lady_Fox [76]

Answer:

171007 1/2

Explanation:

it's a mixed number

3 0

3 years ago

A block of mass 0.84 kg is suspended by a string which is wrapped so that it is at a radius of 0.061 m from the center of a pull

lora16 [44]

Answer:

$E_l = 1.713 J$

Explanation:

Given data:

mass of block is $M_b = 0.84 kg$

radius of block = 0.061 m

moment of inertia is $6.20 \times 10^{-3} kg m^2$

D is distance covered by block = 0.65 m

speed of block is 1.705 m/s

From conservation of momentum we have

$M_b g D = \frac{1}{2} M_b v^2 + \frac{1}{2} I \omega^2 + E_{loss}$

$0.84 \times 9.81 \times 0.65 = \frac{1}{2}\times 0.84 \times 1.705^2 +\frac{1}{2} \times 6.2 \times 10^{-3} [\frac{1.705}{0.061}]^2 + E_l$

solving for energy loss

$E_l = 1.713 J$

3 0

3 years ago

The amount or quality of light that is reflected from a mineral surface is known as __________. The amount or quality of light t

Eddi Din [679]

Answer:

C. Luster

Explanation:

Luster is a phenomenon which refers to the manner with which the outer surface of a mineral reflects light.

Depending on the mineral, the 'luster' can differ. For example, in some minerals, the surface appears to be translucent, while in others, the surface appears to be transparent.

There are different types of luster, but they are categorized majorly into two:

- Metallic luster (the surface of the mineral appears like the surface of a metal).

- Non metallic luster.

7 0

3 years ago

Light of wavelength 550 nm falls on a

Brums [2.3K]

Answer:

The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.

Explanation:

We can describe single slit diffraction phenomenon with the equation:

$a\sin\theta=m\lambda$ (1)

with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum ( $y_{m}$ ) are small compared to the distance between the screen and the slit (x), we can approximate $\sin\theta\approx\tan\theta=\frac{y}{x}$ , using this on (1):

$a\frac{y_{m}}{x}=m\lambda$

solving for y

$y_{m}= \frac{mx\lambda}{a}$

Note that $y_{m}$ is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find $y_{1}$ , $y_{2}$ add them and divide by two: