For the answer to the question above, first find out the gradient.
<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>
<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>
<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>
<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>
<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
Answer:
Rotating the loop until it is perpendicular to the field
Explanation:
Current is induced in a conductor when there is a change in magnetic flux.
The strength of the induced current in a wire loop moving through a magnetic field can be increased or decreased by the following methods:
By increasing the strength of the magnetic field there will be increased in the induced current. If the strength of the magnetic field is decreased then there is a decrease in induced current.
By increasing the speed of the wire there will be increased in the induced current. When the speed of the wire is decreased then there is a decrease in induced current.
By increasing the number of turns of the coil the strength of the induced current can be increased. when there is less number of turns in coils then there is a decrease in induced current.
Rotating the loop until it is perpendicular to the field will not increase the current induced in a wire loop moving through a magnetic field.
Therefore, the option is (c) is correct.
Answer:
All fraction of kinectic energy is lost to barrel of a spring gun of mass 1.8 kg
Explanation:
A ball of mass 0.50 kg is fired with velocity 160 m/s ...
The kinetic energy is given by 1/2mv²
Kinectic energy of the ball = 1/2 *0.5*160²
Kinectic energy = 1/4 *25600
Kinectic energy = 6400 joules.
If no energy is lost to fiction, and the ball sticks to a barrel of a spring gun of mass 1.8 kg with initial velocity zero, all kinetic energy is lost to the barrel of a spring gun of mass 1.8 kg.
Answer:
(a) 272.73 m
(b) 0.338 N/C
Explanation:
frequency, f = 1100 kHz = 1100 x 1000 Hz
E(t) = Eo Sin(2πft)
Eo = 0.62 N/C
(a) Velocity of light, c = 3 x 10^8 m/s
wavelength, λ = c / f = (3 x 10^8) / (1100000) = 272.73 m
Thus, the wavelength is 272.73 m.
(b) at t = 3.1 microsecond = 3.1 x 10^-6 s
E = Eo Sin (2 π ft)
E = 0.62 Sin (2 x 3.14 x 1100 x 10^3 x 3.1 x 10^-6)
E = 0.62 Sin (21.4148)
E = 0.62 x 0.5449 = 0.338 N/C
Thus, the electric field at t = 3.1 microsecond s 0.338 N/C.
