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alexdok [17]
3 years ago
6

What holds solid parties together?​

Chemistry
2 answers:
denis23 [38]3 years ago
7 0

Answer:

Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. Their vibration is related to their kinetic energy. In the solid the particles vibrate in place. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart.

Explanation:

Hope this helped Mark BRAINLIEST!!!

solmaris [256]3 years ago
3 0

Answer:

The cool people like me XD

Explanation:

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Consider the following equation: K + Br → KBr. How many grams of KBr can you make with 1.25g of K?
Dmitry [639]

Answer:

\fbox{3.81 \: grams}

Explanation:

First consider the mol to mol ratio, the mol of a substance is simply the count of atoms in respect to avagadros number (approx. 6.02 × 10²³ molecules) in the period table. 1 mol of an element is simply it's mass count in the periodic table.

5 0
3 years ago
Acid-catalyzed dehydration of 3,3-dimethyl-2-butanol gives three alkenes: 2,3-dimethyl-2-butene, 3,3-dimethyl-1-butene, and 2,3-
Fynjy0 [20]

1,1-hexene > 2,3,3-dimethyl-2-butene > 3-methyl-3-hexene > cis-3-hexene

The Saytzeff rule states that an alkene becomes more stable the more highly substituted it is. Since 2,3-dimethyl-2-butene is the most substituted alkene among the ones listed, it will thus be the most stable.

Ozone treatment of 2,3-dimethyl but-2-ene results in ozoinde, which with further reduction yields propanone and water. Trans-2-butene undergoes ozonolysis, producing the main ozonide. Acetaldehyde, syn- and anti-acetaldehyde oxide, and this main ozonide are the products of its breakdown.

Let's not forget that the alkenes' pi bonds are least stabilized by alkyl groups, making terminal alkenes the least stable of the group. This means that among the alkenes listed, 1-hexene is the least stable.

Learn more about 2,3-dimethyl-2-butene  here brainly.com/question/24146247

#SPJ4.

5 0
2 years ago
Given the reaction
pychu [463]

Answer:

240.17 g Ba3(PO4)2

Explanation:

1. Determine the limiting reactant.

2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O

moles H3PO4 = M x V = 3 x 0.286 = .858 moles H3PO4

moles Ba(OH)2 = M x V = 1.4 x 0.855 = 1.197 moles Ba(OH)2

ratio Ba(OH)2 : H3PO4 = 1.197: .858 = 1.39: 1

stoichiometric ratio Ba(OH)2 : H3PO4  = 3:2

Ba(OH)2is the limiting reactant

MM Ba3(PO4)2 = 601.92 g/mol

g Ba3(PO4)2 = moles Ba(OH)2 x(1 mol Ba3(PO4)2/3 moles Ba(OH)2) x (MM Ba3(PO4)2/ 1mol Ba3(PO4)2) = 1.197 x 1/3 x 601.92 = 240.17 g Ba3(PO4)2

4 0
3 years ago
Can anyone help. I don't understand
maksim [4K]
Brooo we have the same name
7 0
3 years ago
Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s
steposvetlana [31]
We are told we have an oxyacid of the formula HOFO. We will assume the atoms are in this order and will draw a proper lewis structure for this compound by first drawing bonds between each of the 4 atoms and then place the remaining electron pairs on each atom:
      ..    ..    ..
H - O - F - O:
      ··   ··    ··
We can calculate the formal charge of an atom using the following formula:

Formal charge = [# of valence electrons] - [# of non-bonded electrons + # of bonds]

H: Formal charge = [1]-[0+1] = 0

O: Formal charge = [6]-[4+2] = 0

F: Formal charge = [7]-[4+2] = +1

O: Formal charge = [6]-[6+1] = -1

As we can see the overall charge of the molecule is neutral since the fluorine as a +1 charge and the oxygen a -1 charge.
4 0
3 years ago
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