Answer:
Explanation:
First consider the mol to mol ratio, the mol of a substance is simply the count of atoms in respect to avagadros number (approx. 6.02 × 10²³ molecules) in the period table. 1 mol of an element is simply it's mass count in the periodic table.
1,1-hexene > 2,3,3-dimethyl-2-butene > 3-methyl-3-hexene > cis-3-hexene
The Saytzeff rule states that an alkene becomes more stable the more highly substituted it is. Since 2,3-dimethyl-2-butene is the most substituted alkene among the ones listed, it will thus be the most stable.
Ozone treatment of 2,3-dimethyl but-2-ene results in ozoinde, which with further reduction yields propanone and water. Trans-2-butene undergoes ozonolysis, producing the main ozonide. Acetaldehyde, syn- and anti-acetaldehyde oxide, and this main ozonide are the products of its breakdown.
Let's not forget that the alkenes' pi bonds are least stabilized by alkyl groups, making terminal alkenes the least stable of the group. This means that among the alkenes listed, 1-hexene is the least stable.
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Answer:
240.17 g Ba3(PO4)2
Explanation:
1. Determine the limiting reactant.
2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
moles H3PO4 = M x V = 3 x 0.286 = .858 moles H3PO4
moles Ba(OH)2 = M x V = 1.4 x 0.855 = 1.197 moles Ba(OH)2
ratio Ba(OH)2 : H3PO4 = 1.197: .858 = 1.39: 1
stoichiometric ratio Ba(OH)2 : H3PO4 = 3:2
Ba(OH)2is the limiting reactant
MM Ba3(PO4)2 = 601.92 g/mol
g Ba3(PO4)2 = moles Ba(OH)2 x(1 mol Ba3(PO4)2/3 moles Ba(OH)2) x (MM Ba3(PO4)2/ 1mol Ba3(PO4)2) = 1.197 x 1/3 x 601.92 = 240.17 g Ba3(PO4)2
Brooo we have the same name
We are told we have an oxyacid of the formula HOFO. We will assume the atoms are in this order and will draw a proper lewis structure for this compound by first drawing bonds between each of the 4 atoms and then place the remaining electron pairs on each atom:
.. .. ..
H - O - F - O:
·· ·· ··
We can calculate the formal charge of an atom using the following formula:
Formal charge = [# of valence electrons] - [# of non-bonded electrons + # of bonds]
H: Formal charge = [1]-[0+1] = 0
O: Formal charge = [6]-[4+2] = 0
F: Formal charge = [7]-[4+2] = +1
O: Formal charge = [6]-[6+1] = -1
As we can see the overall charge of the molecule is neutral since the fluorine as a +1 charge and the oxygen a -1 charge.
