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Fantom [35]
3 years ago
8

A 6 kg brick is pulled across the flat sidewalk by a horizontal force of 35 N. The brick is experiencing a frictional

Physics
1 answer:
SIZIF [17.4K]3 years ago
6 0
<h3>Answer: Approximately 4.67 m/s^2</h3>

==============================================

Explanation:

Let's say you want to push the brick to the right. The free body diagram will have an arrow pointing right on the rectangle (the brick) and the arrow is labeled with 35 N.

Friction always counteracts whatever force you apply. The friction force arrow will point left and be labeled with 7 N.

The net horizontal force is therefore 35-7 = 28 N and the direction is to the right. The positive net force means you've overcome the force of friction and the brick is moving.

F = 28 is the net force

m = 6 is the mass

a = unknown acceleration

F = m*a .... newton's second law

28 = 6a

6a = 28

a = 28/6

a = 4.67

The acceleration of the brick is approximately 4.67 m/s^2

This means that for every second, the brick's velocity is increasing by about 4.67 m/s.

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Spiderman, whose mass is 74.0 kg, is dangling on the free end of a 11.0-m-long rope, the other end of which is fixed to a tree l
Anestetic [448]

Answer:

W = -1844.513 J

Explanation:

GIVEN DATA:

mass of spider man is m  74 kg

vertical displacement if spider is 11 m

final displacement  =  11 cos 60.6 =  - 6.753 m

change in displacement is  = -6.753 - (-11) = 4.25 m

gravity force act on spiderman is f = mg = 74 × 9.8 = 725.2 N

work done by gravity is W = F \delta r cos\theta

W = 725.2 \times 4.25 \times cos 180

where 180 is the angle between spiderman weight and displacement

W = -1844.513 J

7 0
3 years ago
A wildebeest runs with an average speed of 4.0\,\dfrac{\text m}{\text s}4.0 s m ​ 4, point, 0, start fraction, start text, m, en
devlian [24]

Answer:

60m

Explanation:

4 0
3 years ago
The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.
Reika [66]

Answer:

tan \theta = \mu_s

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

mg sin \theta - \mu_s R =0 (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, \theta the angle of the slope

\mu_s R is the frictional force, with \mu_s being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

R-mg cos \theta = 0

where

R is the normal reaction

mg cos \theta is the component of the weight perpendicular to the slope

Solving for R,

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_s mg cos \theta = 0

Re-arranging the equation,

sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of \mu_s, the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

4 0
4 years ago
A football player runs 20 meters North of a football field, and then 15 meters East. The total motion lasted 15 seconds. What wa
vlada-n [284]
Given:
1st run: 20 meters North
2nd run: 15 meters East
time: 15 seconds

Average speed = total distance covered / total time taken
Ave. Speed = (20m + 15m) / 15s
Ave. Speed = 35m / 15s
Ave. Speed = 2 1/3  meters per second
4 0
3 years ago
Which system of government has a leader that takes power by force
kvv77 [185]

Answer:

The Autocratic system of governance

Explanation:

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5 0
3 years ago
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