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Darina [25.2K]
3 years ago
11

You know that for any object to escape the gravitational pull of a planet, star, and so on, the object must first achieve escape

velocity, or vesc. What velocity must the Veracious achieve to escape Earth
Physics
1 answer:
alisha [4.7K]3 years ago
3 0

Answer:

11.186 * 10^3 m/s

Explanation:

For a Veracious to escape the gravitational pull of the earth it has to a attain

Vesc = \sqrt{\frac{2GM}{R} }  -------- ( 1 )

where: G = ( gravitational constant ) = 6.674 * 10^-11 m^3 kg^-1 s^-2 )

            M = ( mass of earth) =  5.972 * 10^24 kg

            R =  ( Radius of earth ) =  6.371 * 10^6  m  

next we will Input  values into equation ( 1 )

The required Vesc that the Veracious can attain to escape the gravitational pull of the earth = 11.186 * 10^3 m/s

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The pressure exerted on the table due to the book is 200 N/m².

The given parameters;

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The area of the table is calculated as follows;

A = 0.1 x 0.2 = 0.02 m²

The pressure exerted on the table due to the book is calculated as follows;

P = \frac{F}{A}

where;

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P =\frac{F}{A} = \frac{mg}{A} = \frac{0.4 \times 10}{0.02} = 200 \ N/m^2

Thus, the pressure exerted on the table due to the book is 200 N/m².

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When a potential V is applied across a capacitor, a charge q is stored. What charge is stored if the potential across the capaci
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Answer:

q' = 0.5q

Hence, the charge stored is also halved

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