Question

An MRI technician moves his hand from a region of very low (B=0) magnetic field strength into an MRI scanner’s 3.50 T field with his fingers pointing in the direction of the field. He is wearing a ring whose diameter is 2. 0 cm and its resistance is 0.1 Ω.. Assume that it takes 0.40 s to move it into the field. Calculate the change in the magnetic flux in the ring in the above scenario.

Answer 1

Answer:

The change in the magnetic flux in the ring is 10.99 Wb.

Explanation:

Given that,

An MRI technician moves his hand from a region of very low (B=0) magnetic field strength into an MRI scanner’s 3.50 T field with his fingers pointing in the direction of the field.

Diameter of the ring, d = 2 cm

Radius, r = 1 cm

It takes 0.4 s to move it into the field. We need to find the change in magnetic flux in the ring. Magnetic flux is given by :

$\phi=BA\\\\\phi=B\pi r^2\\\\\phi=3.5\pi \times (1)^2\\\\\phi=10.99\ Wb$

So, the change in the magnetic flux in the ring is 10.99 Wb. Hence, this is the required solution.