The motivation to abstain from adding water to concentrated acids is that, with a few acids, amid weakening, a considerable measure of warmth is discharged, by adding the corrosive to the water, the generally extensive measure of water will retain the warmth. On the off chance that you added water to concentrated corrosive when you initially beginning pouring the water, it could get sufficiently hot for the little measure of water that was filled all of a sudden bubble and splatter corrosive on you. Concentrated sulfuric corrosive is most famous for doing this, not all acids get that hot on weakening, but rather in the event that you make a propensity for continually adding the corrosive to water for every one of them, you can't turn out badly.
Answer:
2.76 × 10⁻¹¹
Explanation:
I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.
1. Calculate the free energy of formation of CCl₄
C(s)+ 2Cl₂(g)→ CCl₄(g)
ΔG°/ mol·L⁻¹: 0 0 -65.3
ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹
2. Calculate K
T = (25.0 + 273.15) K = 298.15 K
Answer:
0.0123 moles
Explanation:
Concentration = Moles / Volume of solution
or you can rearrange the formula to get
Moles = concentration (moles/liter) x volume of solution (liter)
First convert your volume to L instead of mL. 35mL = 0.035L
moles = 0.350 moles/liter x 0.035 liter (liters cancel out)
moles = 0.0123
Answer:
The controlled variable of an experiment is the one thing that stays the same in an experiment.
Explanation:
An example would be : if I have two pennies, both dunked in water, but than I change one to be dunked in vinegar, the one dunked in water still is the constant or the controlled variable.
Answer:
D
Explanation:
A and B are completely wrong and C is partial but D is the best option
