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3 years ago

If ms2 is 40.06% sulfur by mass, what is the identity of the metal m?

Chemistry

1 answer:

musickatia [10]3 years ago

4 0

Answer:

The mass percent refers to the mass of an element in a compound. It is one of the ways of expressing concentration. The mass percent of the solution provides the percentage of the amount of solute present in grams of solution.

The mass percentage of S=40.06 % and the molar mass of S= 32. By applying the formula of mass percent,we can calculate the molar mass of M.

The molar mass of M=159.76-64=95.76

We know that the element of molybdenum has molar mass of 96. Therefore, the element M is Molybdenum.

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shusha [124]

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Explanation:

The balanced chemical reaction is,

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]$

Putting the values we get :

$\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]$

$\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]$

$\Delta H=-5314.8kJ$

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = $\frac{5314.8}{2}\times 1=2657.4kJ$

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

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