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-Dominant- [34]

3 years ago

12

which type of organism converts wastes and dead material into nutrients that can be used by plants (1) carnivore (2) herbivore (

3) decomposer (4) producer

1 answer:

Pavlova-9 [17]3 years ago

7 0

Producer hope this helped

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A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat

Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

$\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}$

$\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}$

$\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}$

Using Newton's second law, it is established that F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object $\left(m_{1}+m_{2}\right)$

Now consider both $\mathrm{m}_{1} \text { and } \mathrm{m}_{2}$ as a system, so net force acting on the system is $\text { Force }=\left(m_{1}+m_{2}\right) a$

Substitute the given values in the above formula,

$\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

$\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

5 0

3 years ago

Is a rock that cools quickly after lava rusted through a volcano what is the best description of its texture

gavmur [86]

The physical description would be soft due to the lava cooling the rock.

3 0

3 years ago

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Where is planet mercury located in the solar system?

olya-2409 [2.1K]

Its orbit is between Venus' and the sun.

7 0

3 years ago

A ball is kicked on a planet the size of Earth but with twice the acceleration due to gravity. If the maximum height of the ball

USPshnik [31]

Answer:

The value $t = 1.995 \ s$

Explanation:

From the question we are told that

The acceleration due to gravity is a = 2g

The maximum height is h= 39 m

Generally from the kinematic equation

$s = ut + \frac{1}{2} at^2$

Here u is the velocity of the ball at maximum height before it start falling and the value is 0 m/s

So

$39 = 0* t + \frac{1}{2} (2g)t^2$

$39 = (9.8)t^2$

$t = \sqrt{3.9795918}$

$t = 1.995 \ s$

3 0

3 years ago

Two particles, one with charge − 7.97 μC −7.97 μC and one with charge 7.75 μC, 7.75 μC, are 8.09 cm 8.09 cm apart. What is the m

mr Goodwill [35]

Answer:

Electric force, F = 84.93 N

Explanation:

Given that,

Charge on particle 1, $q_1=-7.97\ \mu C=-7.97\times 10^{-6}\ C$

Charge on particle 1, $q_2=7.75\ \mu C=7.75\times 10^{-6}\ C$

The distance between charges, d = 8.09 cm

To find,

The magnitude of the force that one particle exerts on the other.

Solution,

The electric force of attraction or repulsion is given by the formula as:

$F=\dfrac{kq_1q_2}{d^2}$

k is the electrostatic constant

$F=\dfrac{9\times 10^9\times 7.97\times 10^{-6}\times 7.75\times 10^{-6}}{(8.09\times 10^{-2})^2}$

F = 84.93 N

So, the magnitude of the force that one particle exerts on the other is 84.93 N.

4 0

3 years ago

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