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slega [8]
2 years ago
13

PLZ answer asp The image shows the combustion of methane. Which equation represents this chemical reaction?

Physics
2 answers:
maksim [4K]2 years ago
7 0

The chemical reaction that would represent the combustion of methane would be CH4 + 2O2 = CO2 + 2H2O. Combustion reactions are reactions which involves a substance burning in oxygen.

tankabanditka [31]2 years ago
4 0
The answer is D because CH4+02>2c02+3H20 is a chemical reaction
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What is 0.94kg divided by 2.4n
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Answer:

0.39166666666

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Explanation:

Hope this helps! Please mark as brainliest.

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3 years ago
Which type of mirror would you use to cook a hot dog and why?
alexandr1967 [171]
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2 years ago
A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat
Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}

\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}

\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

5 0
3 years ago
A clay vase on a potter's wheel experiences an angular acceleration of 5.69 rad/s2 due to the application of a 16.0-n m net torq
Digiron [165]
The equivalent of the Newton's second law for rotational motions is:
\tau = I \alpha
where
\tau is the net torque acting on the object
I is its moment of inertia
\alpha is the angular acceleration of the object.

Re-arranging the formula, we get
I= \frac{\tau}{\alpha}
and since we know the net torque acting on the (vase+potter's wheel) system, \tau=16.0 Nm, and its angular acceleration, \alpha = 5.69 rad/s^2, we can calculate the moment of inertia of the system:
I= \frac{\tau}{\alpha}= \frac{16.0 Nm}{5.69 rad/s^2} =2.81 kg m^2
8 0
3 years ago
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