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2 years ago

PLZ answer asp The image shows the combustion of methane. Which equation represents this chemical reaction?

Physics

2 answers:

maksim [4K]2 years ago

7 0

The chemical reaction that would represent the combustion of methane would be CH4 + 2O2 = CO2 + 2H2O. Combustion reactions are reactions which involves a substance burning in oxygen.

tankabanditka [31]2 years ago

4 0

The answer is D because CH4+02>2c02+3H20 is a chemical reaction

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Why are distant objects in the universe moving away from Earth? Because the light they emit is redshifted. Because Earth's gravi

GarryVolchara [31]

Distant objects in the universe moving away from Earth because the universe is expanding.

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3 years ago

On Earth, a scale shows that you weigh 585 N. What would the scale read on the Moon (g = 1.60 m/s2)? N

Serggg [28]

Answer:

95.51 N

Explanation:

First, find the mass in kg:

Fg = 585 N

Fg = m*g

585 N = m*9.8 m/s^2

Then, to find your weight (Fg) on the moon, you use the same equation of

Fg(moon) = m*g, except this time g = 1.60 m/s^2

Fg(moon) = 59.69 kg * 1.60 m/s^2

Fg(moon) = 95.51 N

Hope this helps!! :)

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2 years ago

What surface features does mars have that are also common on earth?

dedylja [7]

<span>Both planets, Mars and the Earth are terrestrial planets. This means that their surface is rocky, they have Mountains, canyons, valleys, ice caps..</span>

4 0

3 years ago

Read 2 more answers

A horizontal 649 N merry-go-round of radius 1.05 m is started from rest by a constant horizontal force of 61.3 N applied tangent

nexus9112 [7]

Answer:

The kinetic energy of the merry-go-round is 632.82 J

Explanation:

Given;

weight of the merry-go-round, W = 649 N

radius of the merry-go-round, r = 1.05 m

applied horizontal force, F = 61.3 N

acceleration due to gravity, g = 9.8 m/s²

mass of merry-go-round, m = W/g

= 649/9.8 = 66.225 kg

moment of inertia of merry-go-round, I = ¹/₂mr²

= ¹/₂ x 66.225 x (1.05)²

= 36.507 kg.m²

Angular acceleration of the merry-go-round, α

τ = Iα = Fr

α = Fr / I

Where;

α is angular acceleration

α = (61.3 x 1.05) / 36.507

α = 1.763 rad/s²

Angular velocity of the merry-go-round, ω

ω = αt

ω = 1.763 x 3.34

ω = 5.888 rad/s

Finally, the kinetic energy of the merry-go-round, K.E

K.E = ¹/₂Iω²

K.E = ¹/₂ x 36.507 x (5.888)²

K.E = 632.82 J

4 0

2 years ago

As a student in a physics lab, you are asked to classify two springs. Right away you notice some differences. The first spring,

strojnjashka [21]

Answer:

C. The spring constant of spring 2 is larger than spring 1.

Explanation:

As we know that spring constant also called the stiffness constant of a spring is the value of force required for the deformation of the spring by a unit length.

Mathematically given as:

$k=\frac{F}{\delta x}$

where:

$k=$ stiffness constant

$F=$ force on the spring

$\delta x=$ change in length of the spring

It is given in the question that spring 1 is easily compressible and requires less force to compress as compared to spring 2 and hence it has lesser stiffness constant than that of spring 2.

3 0

3 years ago