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3 years ago

The boxplot below represents the number of texts sent in two minutes by 11 different freshmen.

Mathematics

1 answer:

Assoli18 [71]3 years ago

8 0

Part A: 9
Part B: 6 and 7

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Can someone help me plz

melisa1 [442]

The answer is B,which is 454 to be exact

7 0

3 years ago

Help asap!!!!!!!!!!!

svlad2 [7]

Answer:

The answer to your question is:

Step-by-step explanation:

12.-

x² - 6x = 5

x² - 6x + (3)² = 5 + (3)²

x² - 6x + 9 = 5 + 9

(x - 3)² = 14

13.- x² - 6x = 12

x² - 6x + (3)² = 12 + (3)²

x² - 6x + 9 = 12 + 9

(x - 3)² = 21

x - 3 = ±√21

x1 = √21 + 3 x2 = -√21 + 3

x1 = 7.58 x2 = -1.58

14.- 2x² - 24x = - 20 Divide by 2

x² - 12 x = -10

x² - 12x + (6)² = - 10 + (6)²

x² - 12x + 36 = - 10 + 36

( x - 6) ² = 26

x - 6 = ±√26

x1 = √26 + 6 x2 = -√26 + 6

x1 = 11.1 x2 = 0.9

3 0

3 years ago

Please help with this MATH question. I would appreciate it, it is the only one I need help with. SOLVING A SYSTEM INCLUDING LINE

makkiz [27]

Answer:

see below and attached

Step-by-step explanation:

To solve a system of quadratic equations:

Equal the equations then rearrange so that it is set to zero.
Use the quadratic formula to solve.

I have done this (see attached workings) but cannot get any of the solutions you've provided. I have even graphed the two functions, and the points of intersection concur with my workings (see attached graph).

4 0

2 years ago

Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min

leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2}$ .

First, we simplify the expression in the numerator of the fraction.

$3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72$

Now, we obtain

$12(x^2-x-6) = 12(x+2)(x-3)$

and the fraction is transformed into

$\frac{3(2x-1)^2 - 75}{x+2} = \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)$

Therefore, the following limit is

$\lim_{x \to -2} \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2} 12(x-3) = 12 \lim_{x \to -2} (x-3)$

You can plug in $-2$ in the equation, hence

$12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60$

6 0

4 years ago

The French club is holding a car wash fundraiser. They are going to charge $20 per car , and expect between 30 and 100 cars. Ide

liberstina [14]

Independent variable = number of cars with domain 30 to 100 cars
Dependent variable = money raised with range $600 to $2000

7 0

4 years ago

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