an object is moving east with a constant speed of 20m/s for 4 seconds.What is the object's acceleration

Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the ap

Verizon [17]

Answer:

The answer is " $1.144 \times 10^{-4} \ m$ ".

Explanation:

$w=\frac{2.44 \lambda L}{D}\\\\D=\frac{2.44 \lambda L}{w}\\\\$

$=\frac{2.44 \times 633 \times 10^{-9}\times 4 }{0.054}\\\\=\frac{6178.08\times 10^{-9}}{0.054}\\\\=1.144 \times 10^{-4} \ m$

8 0

3 years ago

Wine and cheese are complement goods because they are consumed together. What would we expect to happen to the equilibrium quant

notka56 [123]

Explanation:

As wine and cheese are consumed together,it means that they both are complimentary goods.

As per law of demand,the fall in price of a complimentary good would increase the demand and shift the demand curve of the other to the right.

The equilibrium quantity of cheese would increase and shift to right when the price of wine falls.

8 0

3 years ago

Suppose an object is launched from a point 320 feet above the earth with an initial velocity of 128 ft/sec upward, and the only

Ne4ueva [31]

Answer:

(a)Therefore the highest altitude attained by the object is =576 ft .

(b)Therefore the object takes 6 sec to fall to the ground.

Explanation:

Initial velocity: Initial velocity is a velocity from which an object starts to move.

u is usually used for notation of initial notation.

Final velocity: Final velocity is a velocity of an object after certain second from starting.

The final velocity is denoted by v.

Acceleration: The difference of final velocity and initial velocity per unit time

The S.I unit of acceleration is m/s².

(a)

Given that u= 128 ft\sec and g = 32 ft/sec².

At highest point the velocity of the object is 0 i.e v=0

Since the displacement is opposite to the gravity.

Therefore acceleration( a)= -g = -32 ft/sec².

To find the time this to happen we use the following formula

$v=u+at$

Here v=0

⇒0=128+(-32) t

⇒32t=128

⇒t = 4 sec

To determine the height we use the following formula

$s=ut+\frac{1}{2} at^2$

$\Rightarrow s= (128\times4)+\frac{1}{2}\times (-32) \times4^2$

⇒s= 256 ft

Therefore the highest altitude attained by the object is =(320+256)ft=576 ft .

(b)

At the highest point the velocity of the object is 0.

so u=0. a=g= 32 ft/sec² [ since the direction of gravity and the displacement are same] s= 576 ft

To determine the time to fall we use the following formula

$s=ut+\frac{1}{2} at^2$

$\Rightarrow 576 = (0\times t)+\frac{1}{2} \times 32 \times t^2$

$\Rightarrow 16\times t^2=576$

$\Rightarrow t^2=\frac{576}{16}$

$\Rightarrow t^2=36$

⇒t=6 sec

Therefore the object takes 6 sec to fall to the ground.

8 0

3 years ago

If 250 g of calcium chlorate decomposes into calcium chloride and oxygen, what mass of oxygen would be produced?

sineoko [7]

115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

<u>Explanation:</u>

Ca(ClO₃)₂ -->CaCl₂ + 3O₂

One mole of calcium chlorate give three moles of oxygen.

Molar mass of calcium chlorate is

40+(35.5+16*3)*2 = 207g/mol

Molar mass of Oxygen = 32g

1 mole of calcium chlorate decomposes to form 3 moles of oxygen.

So,

207g of Ca(ClO₃)₂ produces 3 X 32g of O₂

250g of Ca(ClO₃)₂ will produce = $\frac{3 X 32}{207} X 250$

= 115.94g of O₂

Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

7 0

3 years ago

CCDs are _____ format detectors, which detect photons with _____ efficiency. analog, high analog, low digital, high digital, low

mars1129 [50]

High digital and high are the answers.

hope this helps

7 0

3 years ago