Answer:
B = basic
Explanation:
Given data:
[OH⁻] = 5.35×10⁻⁴M
pH = ?
Solution:
pOH = -log[OH⁻]
pOH = - [5.35×10⁻⁴]
pOH = 3.272
it is known that,
pH + pOH = 14
pH = 14- pOH
pH = 14 - 3.272
pH = 10.728
The acidic pH is range from zero to less than 7 while 7 pH is neutral and above 7 the pH is basic. So, the given solution is basic.
Answer:
Explanation:
So, the formula for the compound should be:
![XCl_{6}](https://tex.z-dn.net/?f=XCl_%7B6%7D)
Now we assume that we have 1 mol of substance, so we can make calculations to know the molar mass of element X, as follows:
![M_{Cl}=35.45g/mol\\](https://tex.z-dn.net/?f=M_%7BCl%7D%3D35.45g%2Fmol%5C%5C)
So we have that 6 moles weight 212.7g, and we can make a rule of three to know the weight of compound X:
![212.7g\rightarrow 86.9\%\\x\rightarrow 13.1\%\\\\x=\frac{212.7g*13.1}{86.9} =32.06g](https://tex.z-dn.net/?f=212.7g%5Crightarrow%2086.9%5C%25%5C%5Cx%5Crightarrow%2013.1%5C%25%5C%5C%5C%5Cx%3D%5Cfrac%7B212.7g%2A13.1%7D%7B86.9%7D%20%3D32.06g)
As we used 1 mol, we know that the molar mass is 32.06g/mol
So the element has a molar mass of 32.06 g/mol and an oxidation state of +6, with this information, we can assure that the element X is sulfur, so the compound is ![SCl_{6}](https://tex.z-dn.net/?f=SCl_%7B6%7D)