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Evgesh-ka [11]
2 years ago
7

Which of the following describes a spectrum?

Chemistry
2 answers:
natka813 [3]2 years ago
6 0

Answer: The Answer would be C

Explanation: A spectrum is a Range of Wavelengths and Frequencies of Electromagnetic Radition.

konstantin123 [22]2 years ago
4 0

A spectrum is a range of wavelengths or frequencies of electromagnetic radiation.

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200 grams of an organic sample which contains only carbon, hydrogen, and oxygen is analyzed and found to contain 97.30 grams of
ipn [44]
The empirical formula for 200 grams of an organic sample which contains carbon,hydrogen, and oxygen is C3H6O

3 0
3 years ago
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According to the equation, 2 H2 + O2 --> 2 H20, how many moles of oxygen are required to convert 12 moles of hydrogen to wate
DerKrebs [107]

Answer:

6 moles of oxygen, or 3O2.

Explanation:

I would build a proportion for this:

\frac{2(2)}{2}  =  \frac{12}{x}  \\ 4x = 24 \\ x = 6

5 0
3 years ago
Fluorine (F) has seven electrons in its outermost shell. Fluorine _____.
kow [346]
Fluorine is a nonmetal and as such it would need to take in or obtain an electron from a metal to have a stable octet, or full number of 8 electrons in its valence shell. Thus due to the indifference of electrons and protons it becomes an anion, a negatively charged ion.
7 0
3 years ago
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The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c
crimeas [40]

Answer : The rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 785.0K = ?

Ea = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 785.0K

Now put all the given values in this formula, we get:

\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]

K_2=1.45\times 10^{-2}s^{-1}

Therefore, the rate constant at 785.0 K is, 1.45\times 10^{-2}s^{-1}

7 0
3 years ago
A 2.3 kg object has 15 ) of kinetic energy. Calculate its speed.
chubhunter [2.5K]

Answer:

<h3>The answer is option D</h3>

Explanation:

To find the speed given the kinetic energy and mass we use the formula

v =  \sqrt{ \frac{2KE}{m} }  \\

where

m is the mass

v is the speed

From the question

KE = 15 J

m = 2.3 kg

We have

v =  \sqrt{ \frac{2 \times 15}{2.3} }  =  \sqrt{ \frac{30}{2.3} }  \\  = 3.61157559...

We have the final answer as

<h3>3.6 m/s</h3>

Hope this helps you

7 0
3 years ago
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