Answer: Thus concentration of 
in 
is 0.011 and in 
is 0.814
Explanation:
To calculate the concentration of , we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is
We are given:
Putting values in above equation, we get:
The concentration in is 
Thus concentration of is 
and 
The products of this reaction between aluminum and sulfuric acid are two: hydrogen and aluminum sulfate.
<h3>What are the products in a reaction?</h3>
This concept refers to the substances obtained at the end of the reaction.
<h3>What does it mean to balance an equation?</h3>
It means to make sure there are the same molecules in the reactants and products.
<h3>What are the products in this reaction?</h3>
- Al + H2SO4 = Al2 (SO4)3 + H2
- Al2 (SO4)3 = Aluminium sulfate
- H = Hydrogen
<h3>What is the balanced equation?</h3>
2Al + 3H2SO4 = Al2 (SO4)3 + 3H2
Learn more about chemical reaction in: brainly.com/question/3461108
Answer:
hope this answer will help you.
<h3><u>Answer;</u></h3>
= 3032.15 kPa
<h3><u>Explanation;</u></h3>
Using the equation;
PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.
Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles
Therefore;
Pressure = nRT/V
= (5 × 0.08206 × 547)/7.5 L
= 29.925 atm
But; 1 atm = 101325 pascals
Hence; Pressure = 3032150.63 pascals
<u>= 3032.15 kPa</u>
