which atomic particle determines the chemical behavior of an atom the nucleus, neutron, electron, proton or none of these

1 answer:

7 0

The chemical behavior of an atoms is determine by the formation or destruction of chemical bonds. The chemical bonds are the result of the interaction of the electrons of the atoms. Chemical properties of the atoms are given by how attached are the shell electrons attached to the nucleus and how they interact with other atoms. Chemical changes are the result of exchange valence electrons of the atoms. So, the answer is the atomic particle that determines the chemical behavior of an atom is the electron, because it is the particle that is active in chemical bonding.

You might be interested in

When a supply of hydrogen gas is held in a 4 liter container at 47°C it exerts a pressure

Archy [21]

Answer:

helooooooo im bored

the answer id 1423c

Explanation:

4 0

2 years ago

An atom that has 13 protons and 15 neutrons is isotope of the element A.) nickel B.) silicon C.) aluminum D.) phosphorus. Why?

joja [24]

An atom that has 13 protons and 15 neutrons is isotope of Aluminium (answer C)

Explanation

Isotope is a form of the same element with the equal number of protons but difference number of neutrons in their nuclei.

In other words isotope has the same atomic number but different mass number.

Atomic number of a element is determined by number of protons of an element.

from the periodic table Aluminum in atomic number 13 therefore it has 13 protons therefore an atom that has 13 protons and 15 neutrons is a isotope of Aluminium.

6 0

3 years ago

Read 2 more answers

Question 38 (1 point)

Fiesta28 [93]

Answer: Protons because they have a positive charge.

Explanation:

8 0

3 years ago

I will give brainliest and 76 points

katen-ka-za [31]

Answer:

number 5 is the answer

Explanation:

8 0

2 years ago

Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(

kkurt [141]

Answer: The $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)$ $\Delta H^o_{rxn}=?$