The anode is zinc, and the cathode is the nail
Answer:
Explanation:
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In this case, according to the given chemical reaction:
CaCO3(s)→CaO(s)+CO2(g)
In which the amounts are unfortunately given, we can however, assume the information of similar problems so you can further modify the numbers but follow the same work:
CaCO3 = 25.3 g
CaO = 14.9 g
CO2 = 33.7 g
Thus, since just CO2 is involved on the equilibrium expression because CaCO3 and CaO are solid, we can compute the moles of the CO2 at equilibrium and further compute the concentration in the 9.0-L vessel:
Thus, we proceed with the equilibrium expression to obtain:
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Answer:
a)23.2 L
b)68.3kPa
c)7.5 atm
d)60.5L
e)1.67 atm
Explanation:
From Boyle's law:
P1V1=P2V2
P1= 748mmHg
P2=725mmHg
V1= 22.5L
V2??
V2= P1V1/P2= 748×22.5/725= 23.2 L
b)
V1=4.0L
P1= 205×10^3Pa
V2= 12.0L
P2=???
P2= P1V1/V2= 205×10^3×4/12
P2= 68.3×10^3 Pa or 68.3kPa
c)
P1= 1 atm
V1= 196.0L
P2= ??
V2= 26.0L
P2= P1V1/V2=1×196.0/26.0
P2= 7.5 atm
d)
V1= 40.0L
P1= 12.7×10^3Pa
V2=???
P2= 8.4×103Pa
V2= P1V1/P2= 12.7×10^3×40.0/8.4×103
V2=60.5L
e)
V1= 100mL
P1= 1atm
V2= 60mL
P2=???
P2= P1V1/V2= 1×100/60
P2= 1.67 atm