Answer:
23.9g of Fe₂O₃ are produced
Explanation:
<em>Are formed when 16.7g of Fe reacts completely...</em>
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Based on the reaction:
4Fe + O₃ → 2Fe₂O₃
<em>4 moles of Iron react per 1 mole of O₃ producing 2 moles of Fe₂O₃.</em>
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To solve this question we need to convert the mass of iron to moles. The ratio of reaction is 2:1 -That is, 2 moles of Fe produce 1 mole of Fe₂O₃-. Thus, we can find the moles of Fe₂O₃ produced and its mass:
<em>Moles Fe -Molar mass: 55.845g/mol-:</em>
16.7g Fe * (1mol / 55.845g) = 0.299 moles of Fe
<em>Moles Fe₂O₃:</em>
0.299 moles Fe * (2 mol Fe₂O₃ / 4 mol Fe) = 0.150 moles Fe₂O₃
<em>Mass Fe₂O₃ -Molar mass 159.69g/mol-:</em>
0.150 moles Fe₂O₃ * (159.69g / mol) =
<h3>23.9g of Fe₂O₃ are produced</h3>
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