Iron (III) oxide is formed when Iron combines with oxygen in the air. How many grams of Fe₂O₃ are formed when 16.7 grams of reac
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Answer: Enthalpy for the dissolution reaction of one mole of aluminum nitrate is -158 kJ/mol.
Explanation:
It is known that the density of water is 1 g/mL. So, mass of water will be calculated as follows.
Mass = volume × density
=
= 103.2 g
Specific heat of water is 4.18 .
Now, we will calculate the enthalpy of solution as follows.
=
= 2372.5 J
As, 1 J = . So, 2372.5 J will be converted into kJ as follows.
= 2.37 kJ
Molar mass of = 213 g/mol
Hence, moles of will be calculated as follows.
Moles of =
= 0.015
Therefore, enthalpy for the dissolution will be calculated as follows.
= -158 kJ/mol
Thus, we can conclude that enthalpy for the dissolution reaction of one mole of aluminum nitrate is -158 kJ/mol.