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Mashcka [7]
3 years ago
9

When would a cell use Active Transport? Mark all that apply.

Chemistry
1 answer:
Jobisdone [24]3 years ago
6 0

Answer:

Option B, When the cell needs to move a compound against its concentration gradient.

Explanation:

A cell uses active transport when it has to transport substances against the concentration gradient across its membrane.

In active transport additional energy is used (generally provided by energy molecules like ATP) to push the substance across any membrane from low concentration side  to high concentration side.

Option B is correct

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Which is the correct equilibrium constant expression for the following reaction? Fe2O3(s) + 3H2(g) --> 2Fe(s) + 3H2O(g) Kc =
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Answer:

The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

Explanation:

Step 1: Data given

For the reaction aA + bB ⇆ cC + dD

the equilibrium constant Kc = [C]^c * [D]^d/[B]^b*[A]^a

Step 2: The balanced equation

Fe2O3(s) + 3H2(g) --> 2Fe(s) + 3H2O(g)

Step 3: Calculate the equilibrium constant Kc

Kc =  [C]^c * [D]^d/[B]^b*[A]^a

⇒with [C] = [Fe]

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⇒with d = 3

⇒with [A] = [Fe2O3]

⇒with a = 1

⇒with [B] = [H2]

⇒with b = 3

Kc =  [C]^c * [D]^d/[B]^b*[A]^a

Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

The equilibrium constant Kc = [Fe]²*[H2O]³ / [Fe2O3][H2]³

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