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2 years ago

Question 25 pts

Chemistry

1 answer:

yawa3891 [41]2 years ago

4 0

Answer:

B will give up two electrons to form bonds.

Explanation:

B has 12 electrons, it means that the electronic configuration of B is; 1s2 2s2 2p6 3s2. The implication of this is that B must be an element of group 2 since it has an outermost electron configuration of ns2.

The elements of group 2 form ionic bonds by loss of two electrons. This implies that B will form bonds by loss of two electrons.

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How can a chemical reaction be sped up? Select from the drop-down menu to correctly complete the statement. Add a Choose... that

Reika [66]

Answer:

A: catalyst

Explanation:

In Chemistry, the rate of reaction of chemical elements (reactants) can be sped to produce a chemical compound or elements (products), through the addition of a catalyst that is unaffected by the reaction.

This ultimately implies that, to speed up a chemical reaction, add a catalyst that is unaffected by a reaction.

For example, an enzyme refers to a biological catalyst that is typically used to speed up (accelerate) the rate of a chemical reaction by lowering the activation energy of its reactants.

An enzyme can be defined as a biological catalyst that typically lowers the activation energy of a biological reaction. When the activation energy of a reaction is low, the rate of the reaction would be faster. Therefore, an enzyme speeds or catalyzes the rate of a reaction by lowering its activation energy.

Generally, an increase in temperature increases or speeds up the rate of a reaction while low temperature limits or reduces the rate of a reaction. The optimal temperature for enzymes in the human body is around 37 degrees celsius.

3 0

2 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

2 years ago

Using the method of initial rates for the reaction a → b, if the initial concentration of a is doubled and the rate of reaction

zmey [24]

Answer is: reaction is second order with respect to a.
This second order reaction is proportional to the square of the concentration of reactant a.
rate of reaction = k[a]².
k is second order rate constant and have unit M⁻¹·s⁻¹.
Integrated rate law for this reaction: 1/[a]=1/[a]₀ + kt.
t is time in seconds..

4 0

2 years ago

Each carbon atom of benzene is involved in two ________

coldgirl [10]

Answer:

Benzene is a combination of carbon and hydrogen atoms. The hybridization is sp2 type. During the hybridization of benzene, each carbon atom forms different bonds with two other similar carbon atoms instead of just one.

hope it helps!

please mark as the brainliest!

7 0

2 years ago

Question 11 : Why was Newlands law of octaves rejected?____________

KatRina [158]

It could not hold good for elements heaver than calcium.

7 0

2 years ago