If a gas in a balloon occupies 2.25 L at 298 K and 300 kPa, the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.
<h3>How to calculate temperature?</h3>
The temperature of an ideal gas can be calculated using the following formula:
P1V1/T1 = P2V2/T2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
- T1 = initial temperature
- T2 = final temperature
According to the information given in this question;
- P1 = 300kpa = 2.96 atm
- P2 = 2.17 atm
- V1 = 2.25L
- V2 = 3.50L
- T1 = 298K
- T2 = ?
2.96 × 2.25/298 = 2.17 × 3.5/T2
0.022T2 = 7.595
T2 = 7.595 ÷ 0.022
T2 = 345.23K
Therefore, if a gas in a balloon occupies 2.25 L at 298 K and 300 kPa. the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.
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Answer:
A or D because the chemical reaction is long
Answer:
A.It is a reaction involving pi-electrons.
D.It is *not* a reaction favored by entropy considerations.
Explanation:
The Diels-Alder reaction is a [4+2]- cycloadition that involoves pi-electrons (4 from the diene and 2 from the dienophile).
The reaction is favored by the formation of new sigma bond, since they are more stable than pi-bonds. This reaction is not favored by entropy because there are 2 reactants and one product and the order increases.
The reaction happens in one step.
