I can someone help me and also I gtg so ill be back in a bit

A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an a

goldenfox [79]

According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N

<h3>What does Newton's third law say ?</h3>

The law state that in every action, there will be equal and opposite reaction.

Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.

Let us first calculate the force involved in the acceleration of the rocket by using the formula

F = ma

Where mass m = 87.4 kg, acceleration a = 69.2 m/s2

Substitute the two parameters into the formula

F = 87.4 x 69.2

F = 6048.08 N

According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.

Therefore, the normal force acting on the astronaut is -6048 N approximately

Learn more about forces here: brainly.com/question/12970081

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7 0

2 years ago

Two objects are dropped from rest from the same height. Object A falls through a distance during a time t, and object B falls th

UNO [17]

Answer:

Distance covered by B is 4 times distance covered by A

Explanation:

For an object in free fall starting from rest, the distance covered by the object in a time t is

$s=\frac{1}{2}gt^2$

where

s is the distance covered

g is the acceleration due to gravity

t is the time elapsed

In this problem:

- Object A falls through a distance $s_A$ during a time t, so the distance covered by object A is

$s_A=\frac{1}{2}gt^2$

- Object B falls through a distance $s_B$ during a time 2t, so the distance covered by object B is

$s_B=\frac{1}{2}g(2t)^2 = 4(\frac{1}{2}gt^2)=4s_A$

So, the distance covered by object B is 4 times the distance covered by object A.

5 0

2 years ago

Jennifer works for an automaker and tests the safety performance of cars. she watches a 2,000-kilogram car crash into a wall wit

Kipish [7]

The acceleration of the car at impact is 15m/s².

<h3>What is Newton's Second Law of Motion?</h3>

Newton's second law provides a precise explanation of the modifications that a force can make to a body's motion. According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is equal to the sum of its mass and velocity. Similar to velocity, momentum has both a magnitude and a direction, making it a vector quantity.

acceleration - rate of change of velocity with time, both in terms of speed and direction. A point or object going straight forward is accelerated when it accelerates or decelerates.

There are three types of accelerated motions :

uniform acceleration,
non-uniform acceleration
average acceleration.

express all the units in their most basic form.

kg, newton = kg*m/s², acceleration =m/s²

$\frac{ 30000 kg*m/s^{2} }{ 2000 kg} = 15m/s^{2}$

to learn more about Newton's Second law of Motion - brainly.com/question/13447525

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3 0

1 year ago

F-40N<br>m=5k<br>k = 0,2<br>a=? <br><br><br>

tester [92]

Answer:

1......... .......... ......

3 0

2 years ago

A beam of unpolarized light with intensity I0 falls first upon a polarizer with transmission axis θTA,1 then upon a second polar

loris [4]

Answer:

The intensity I₂ of the light beam emerging from the second polarizer is zero.

Explanation:

Given:

Intensity of first polarizer = Io/2

For the second polarizer, the intensity is equal:

$I_{2} =\frac{I_{o} }{2} (cos\theta )^{2} =\frac{I_{o} }{2} (cos90)^{2} =0$

5 0

3 years ago