Hi there!
According to Newton's second law:
∑F = m · a, where:
∑F = net force (N = kgm/s²)
m = mass (kg)
a = acceleration (m/s²)
Rearrange to solve for acceleration:
F/m = a
20N / 4.0kg = 5 m/s²
Position is measured in meters (m), so it is a base quantity.
<h3>What is base quantity?</h3>
A base or fundamental quantity is a physical quantity, in which other quantities are derived from.
Example of fundamental quantities;
- Mass
- Length (position)
- Time
- Temperature
- Amount of substance
<h3>What is a derived quantity?</h3>
Derived quantities are those quantities obtained or expressed from fundamental quantities.
Example of derived quantities;
- Speed
- Acceleration
- Volume
- Area
- Density, etc
Thus, we can conclude that position measured in meters (m) is a base quantity.
Learn more about base quantities here: brainly.com/question/14480063
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Answer:
51.96 m/s^-1
Explanation:
a) see the attachment
b) As we know the velocity of the projectile has two component, horizontal velocity v_ox. and vertical velocity v_oy as shown in the figure. At the highest point of the trajectory, the projectile has only horizontal velocity and vertical velocity is zero. Therefore at the highest point of the trajectory, the velocity of the projectile will be
v_ox=v_o*cosФ
=60*cos (30)
= 51.96 m/s^-1
