B because N and N don't connect
Calculate the heat gained by the water first.
q = mCpΔT
m = 20.0 g
Cp = 4.186 J/g°C
ΔT = T(final) - T(initial) = 15.0°C - 10.0°C = 5.0°C
q = (20.0)(4.186)(5.0) = 419 J
This is equal to the heat lost by the metal, so calculate Cp for the metal, given:
q = -419 J (negative because heat was lost)
m = 5.00 g
ΔT = 15.0°C - 100.0°C = -85.0°C (negative because the temperature decreased)
q = mCpΔT —> Solve for Cp —> Cp = q/mΔT
Cp = -419 / (5.00 • -85.0) = 0.986 J/g°C
Answer:
Explanation:
From the question we are told that
mass of sample
volume of water
volume for extraction
partition (distribution) coefficient water
initial extraction removal
Generally the equation for the weight of sample is mathematically given by
Generally the weight extracted is therefore
is extracted with 60ml solvent .
Therefore volume of solvent (y) that would be necessary to remove an additional 7.0g
Answer:
<h3>The answer is 103.82 moles</h3>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>103.82 moles</h3>
Hope this helps you
15.999 u I believe. I hope this helps. :)