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Svetllana [295]
3 years ago
13

PLEASEEE HELPPPP....PLEASEEEE

Chemistry
2 answers:
julia-pushkina [17]3 years ago
5 0

Answer: Choice B is correct. \Delta G=-89kJ and E^0_c_e_l_l=+0.46V

Explanation: \Delta G stands for Gibbs free energy equation. A reaction is spontaneous if \Delta G is negative and the reaction non spontaneous if \Delta G is positive.

For a cell, \Delta G is calculated from the cell potential using the equation:

\Delta G=-nFE^0_c_e_l_l

where, n is the moles of electrons transferred in a balanced equation, F is the faraday constant and E^0_c_e_l_l is standard cell potential.

From the above equation, \Delta G could only be negative if E^0_c_e_l_l is positive as the equation has negative sign.

So, the only correct choice is the one for which E^0_c_e_l_l is positive and \Delta G is negative.

Hence. choice B is correct.

Kobotan [32]3 years ago
4 0
For a reaction to be spontaneous, ΔG has to be negative and E° cell is positive. 

the answer is B
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A sample in the laboratory is found to contain 3.36 grams of hydrogen, 20.00 grams of carbon, and 26.64 grams of oxygen. The mol
KonstantinChe [14]

Answer:

Empirical formula is CH₂O.

Molecular formula = C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 3.36 g

Mass of carbon = 20.00 g

Mass of oxygen = 26.64 g

Molar mass of compound = 180.156 g/mol

Empirical formula = ?

Molecular formula = ?

Solution:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

Number of gram atoms of H = 3.36 / 1.01 = 3.3

Number of gram atoms of O = 26.64 / 16 = 1.7

Number of gram atoms of C = 20 / 12 = 1.7

Atomic ratio:

            C                      :        H            :         O

           1.7/1.7                :     3.3/1.7       :       1.7/1.7

              1                     :           2          :        1

C : H : O = 1 : 2 : 1

Empirical formula is CH₂O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = CH₂O = 12×1 + 2× + 16

Empirical formula mass = 30

n = 180.156 / 30

n = 6

Molecular formula = n (empirical formula)

Molecular formula = 6 (CH₂O)

Molecular formula = C₆H₁₂O₆

5 0
3 years ago
A pool owner adds a compound containing chlorine to the pool to disinfect it. However, too much of the compound is added. As a r
MrMuchimi

Answer: He could add a base to the pool to neutralize the acid.

Explanation:

Chlorine is used to disinfect the pools as it produces hypochlorous acid in water. This hypochlorous acid is unstable and gives hydrochloric acid and nascent oxygen which is used to disinfect.

Cl_2+H_2O\rightarrow HOCl

HOCl\rightarrow HCl+O

The excess acid is neutralized by adding base which produces salt and water and thus decrease the acidity.

Acid+Base\rightarrow Salt+water

Adding more acid would increase the acidity further.

3 0
3 years ago
Read 2 more answers
a metal melts at 450°c.is this property of the metal classified as chemical or physical ?explain your choice
avanturin [10]
Chemical properties describe how things undergo chemical reactions, while physical properties describe how things behave when they're not undergoing reactions.

In the case of melting a metal, the melted metal continues to be the same material - just in a liquid rather than a solid form.  As a result, melting (and all phase changes, for that matter) is a physical change and the ability of the metal to melt at 450 degrees is a physical property.
3 0
4 years ago
Plz help!!! This is timed!!!
pogonyaev
58.7 %

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7 0
2 years ago
Consider the following half-reactions and their standard reduction potential values to answer the following questions.
Ganezh [65]

Answer:

Br2 (l) + 2e- ---------> 2Br- (aq) E° = 1.08 V cathode

Cu2+ (aq) + e- --------->Cu+ (aq) E° = 0.15 V anode

Explanation:

We have to first state the fact that the reaction having the most positive reduction potential occurs at the cathode in any spontaneous electrochemical cell. The half reaction with the less positive electrode potential usually occurs at the anode.

The overall reaction equation is;

2Cu2+ (aq) + Br2 (l) ----->2Cu+ (aq) + 2Br- (aq)

E°cell= E°cathode - E°anode

E°cathode= 1.08 V

E°anode= 0.15V

E°cell = 1.08-0.15 = 0.93 V

But

∆G°= -nFE°cell

n= 2, F=96500C, E°cell= 0.93V

∆G° = -(2× 96500× 0.93)

∆G= -179490 J

But;

∆G = -RTlnK

R=8.314 JK-1

T= 25+273= 298K

Kc= the unknown

∆G° = -179490 J

Substituting values and making lnK the subject of the formula

lnK= ∆G/-RT

lnK= -( -179490/8.314 × 298)

lnK= 72.45

K= e^72.45

K= 2.91×10^31

4 0
3 years ago
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