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Svetllana [295]
3 years ago
13

PLEASEEE HELPPPP....PLEASEEEE

Chemistry
2 answers:
julia-pushkina [17]3 years ago
5 0

Answer: Choice B is correct. \Delta G=-89kJ and E^0_c_e_l_l=+0.46V

Explanation: \Delta G stands for Gibbs free energy equation. A reaction is spontaneous if \Delta G is negative and the reaction non spontaneous if \Delta G is positive.

For a cell, \Delta G is calculated from the cell potential using the equation:

\Delta G=-nFE^0_c_e_l_l

where, n is the moles of electrons transferred in a balanced equation, F is the faraday constant and E^0_c_e_l_l is standard cell potential.

From the above equation, \Delta G could only be negative if E^0_c_e_l_l is positive as the equation has negative sign.

So, the only correct choice is the one for which E^0_c_e_l_l is positive and \Delta G is negative.

Hence. choice B is correct.

Kobotan [32]3 years ago
4 0
For a reaction to be spontaneous, ΔG has to be negative and E° cell is positive. 

the answer is B
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7 0
4 years ago
what is the limiting reactant in the reaction of 12.0 g of SO2 with 8.0 g of H2S and their reaction? what mass of sulfur will be
larisa86 [58]
The balanced equation for the reaction is as follows;
2H₂S + SO₂ —> 2H₂O + 3S
Stoichiometry of H₂S to SO₂ is 2:1
Limiting reactant is fully used up in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of H₂S moles - 8.0 g / 34 g/mol = 0.24 mol of H₂S
Number of SO₂ moles = 12.0 g / 64 g/mol = 0.188 mol of SO₂
According to molar ratio of 2:1
If we assume H₂S to be the limiting reactant
2 mol of H₂S reacts with 1 mol of SO₂ 
Therefore 0.24 mol of H₂S requires - 1/2 x 0.24 = 0.12 mol of SO₂ 
But 0.188 mol of SO₂ is present therefore SO₂ is in excess and H₂S is the limiting reactant.
H₂S is the limiting reactant
Amount of S produced depends on amount of H₂S present
Stoichiometry of H₂S to S is 2:3
2 mol of H₂S forms 3 mol of S
Therefore 0.24 mol of H₂S forms - 3/2 x 0.24 mol = 0.36 mol of S
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7 0
3 years ago
8CO + 17H2 → C8H18 + 8H2O
nekit [7.7K]

\frac{6.50mole CO}{1} \frac{17mole H2}{8mole CO}\frac{2 gram H2}{1mole H2}  =27.625

3 sig figs= 27.6

4 0
3 years ago
I NEED THIS ASAP Someone please help me
IceJOKER [234]

Answer:

B. Four moles of water were produced from this reaction.

Explanation:

I took the test and got it correct

8 0
3 years ago
Read 2 more answers
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