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Svetllana [295]
2 years ago
13

PLEASEEE HELPPPP....PLEASEEEE

Chemistry
2 answers:
julia-pushkina [17]2 years ago
5 0

Answer: Choice B is correct. \Delta G=-89kJ and E^0_c_e_l_l=+0.46V

Explanation: \Delta G stands for Gibbs free energy equation. A reaction is spontaneous if \Delta G is negative and the reaction non spontaneous if \Delta G is positive.

For a cell, \Delta G is calculated from the cell potential using the equation:

\Delta G=-nFE^0_c_e_l_l

where, n is the moles of electrons transferred in a balanced equation, F is the faraday constant and E^0_c_e_l_l is standard cell potential.

From the above equation, \Delta G could only be negative if E^0_c_e_l_l is positive as the equation has negative sign.

So, the only correct choice is the one for which E^0_c_e_l_l is positive and \Delta G is negative.

Hence. choice B is correct.

Kobotan [32]2 years ago
4 0
For a reaction to be spontaneous, ΔG has to be negative and E° cell is positive. 

the answer is B
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A chemist titrates of a hypochlorous acid solution with solution at . Calculate the pH at equivalence. The of hypochlorous acid
const2013 [10]

The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

<u>Answer:</u> The pH of the solution is 10.09

<u>Explanation:</u>

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=0.2412M\\V_1=110.0mL\\n_2=1\\M_2=0.0613M\\V_2=?mL

Putting values in above equation, we get:

1\times 0.2412\times 110.0=1\times 0.0613\times V_2\\\\V_2=\frac{1\times 0.2412\times 110.0}{1\times 0.0613}=432.8mL

At equivalence, the number of moles of acid is equal to the number of moles of base. Also, the moles of salt which is NaClO will also be the same.

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

  • <u>For HClO:</u>

Molarity of HClO solution = 0.2412 M

Volume of solution = 110.0 mL

Putting values in equation 1, we get:

0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol

  • <u>For NaClO:</u>

Moles of NaClO = 0.026532 moles

Volume of solution = [432.8 + 110] mL = 542.8 mL

Putting values in above equation, we get:

\text{Molarity of NaClO}=\frac{0.026532\times 1000}{542.8}=0.0489M

To calculate the pH of the solution, we use the equation:

pH=7+\frac{1}{2}[pK_a+\log C]

where,

pK_a = negative logarithm of weak acid which is hypochlorous acid = 7.50

C = concentration of the salt = 0.0489 M

Putting values in above equation, we get:

pH=7+\frac{1}{2}[7.50+\log (0.0489)]\\\\pH=7+3.09=10.09

Hence, the pH of the solution is 10.09

4 0
3 years ago
6. What is the mass of the object if the net force acting on it was 356 N and the acceleration rate
Marina86 [1]

The mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.

<h3>How to calculate mass?</h3>

The mass of an object can be calculated using the following formula:

F = ma

Where;

  • F = force (N)
  • m = mass (kg)
  • a = acceleration (m/s²)

m = F/a

m = 356/4

m = 89kg

Therefore, the mass of an object with a net force of 356N and an acceleration rate of 4m/s² is 89kg.

Learn more about mass at: brainly.com/question/19694949

8 0
2 years ago
What is the empirical formula for P4O10?
Sphinxa [80]

Answer: P2O5

Explanation: You divide both subscripts by 2 to get the empirical formula.

8 0
2 years ago
Read 2 more answers
Hydroxylamine is a weak molecular base with kb = 6.6 x 10-9. what is the ph of a 0.0500 m solution of hydroxylamine?
7nadin3 [17]
Answer is: pH of hydroxylamine solution is 9,23.

Kb(NH₂OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₂OH)<span> = 0,0500 M = 0,05 mol/L.
c(NH</span>₂⁺) = c(OH⁻) = x.

c(NH₂OH<span>) = 0,05 mol/L - x.
Kb = c(NH</span>₂⁺) · c(OH⁻) / c(NH₂OH).

0,0000000066 = x² /  (0,05 mol/L - x). 

solve quadratic equation: x = c(OH⁻) = 0,000018 mol/L.<span>
pOH = -log(</span>0,000018 mol/L) = 4,74.<span>
pH = 14 - 4,74 = 9,23.</span>


4 0
3 years ago
Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t
Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is 1.743\times 10^2g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:  

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol

The chemical equation for the hydrogenation of decene follows:

C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = \frac{1}{1}\times 1.225=1.225mol of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g

Hence, the mass of decane produced is 1.743\times 10^2g

5 0
3 years ago
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