%error = |(original value - mistaken value)| / original value * 100%
Original value = 1.2 x 10^-12
Mistaken value = 1.7 x 10^-10
%error = | [(1.2 x 10^-12) - (1.7 x 10^-10)] | / 1.2 x 10^-12 x 100%
%error = (1.688 x 10^-10 / 1.2 x 10^-12) x 100%
%error = 1.172222222 x 10^17
The nurse<span> is </span>caring<span> for a </span>client<span> with a temperature of 104.5 degrees Fahrenheit. A health </span>care provider<span> prescribes 500 mg of an antibiotic intravenous While undergoing a soapsuds </span>enema, theclient reports abdominal<span> cramping.</span>
Molality= moles of solute /kg of solvent
moles of solute= mass/molar mass
moles of solute= 3.94 g / (342 g/mol)
moles of solute= 0.01 mol
molality= 0.01 mol / 0.285 kg
molality= 0.04 m
We use acids and bases in everyday life for cooking and cleaning