Answer:
Aqueous solution of ionic compounds conduct electricity while solid ionic compounds don't.
Explanation:
Ionic compound conduct electricity when liquid or in aqueous solution that is resolved in water because the ionic bonds of the compound become weak and the ions are free to move from place to place.
Ionic compounds don't conduct electricity while in solid state because the ionic bonds are to strong and ions cannot move around with lack of space for movement which makes the electric conductivity zero.
Answer:
n this question, we are asked to find the probability that
R1 is normally distributed with mean 65 and standard deviation 10
R2 is normally distributed with mean 75 and standard deviation 5
Both resistor are connected in series.
We need to find P(R2>R1)
the we can re write as,
P(R2>R1) = P(R2-R1>R1-R1)
P(R2>R1) = P(R2-R1>0)
P(R2>R1) = P(R>0)
Where;
R = R2 - R1
Since both and are independent random variable and normally distributed, we can do the linear combinations of mean and standard deviations.
u = u2-u1
u = 75 - 65 = 10ohm
sd = √sd1² + sd2²
sd = √10²+5²
sd = √100+25 = 11.18ohm
Now we will calculate the z-score, to find P( R>0 )
Z = ( X -u)/sd
the z score of 0 is
z = 0 - 10/11.18
z= - 0.89
Answer:
The mass flow rate of air through the compressor is = 1.044
Explanation:
Mass flow rate refrigerant = 0.1
= - 0 °c = 273 K
= 50 °c = 323 K
= 3 KW
= 20 °c = 293 K
= 30 °c = 303 K
From the continuity equation
= 0.1
Put all the values in above formula
0.1 × 1.5 × ( 273 - 323 ) + 3 = × 1.005 × ( 303 - 293 )
10.5 = × 10.05
= 1.044
Therefore the mass flow rate of air through the compressor is = 1.044
As noted earlier, in sediments, or in any porous system, the presence of solid particles causes the diffusion paths of species to deviate from straight lines. Consequently, the diffusion coefficients of species must be corrected for the tortuosity.