1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kobotan [32]
3 years ago
10

7. Which of the following is a disadvantage of an electromagnet?

Engineering
1 answer:
Sati [7]3 years ago
7 0

Answer:

I think

electromagnets require power to operate

You might be interested in
Una frase de: ama la vida quien___________________________________
TEA [102]

Answer:

A phrase from: who loves life

Explanation:

5 0
3 years ago
A task is something that you can physically do.
Jet001 [13]
The answer is T because a task is getting something done
5 0
3 years ago
Read 2 more answers
What is the purpose of a gusset or gusset plate used in the construction and repair of aircraft structures?
spin [16.1K]

Answer:

To join and reinforce intersecting structural members

Explanation:

The purpose of a gusset or gusset plate used in the construction and repair of aircraft structures is to join and reinforce intersecting structural members

5 0
2 years ago
Lets assume, a represents the edge length (lattice constant) of a BCC unit cell and R represents the radius of the atom in the u
uranmaximum [27]

Answer:

4\ R=\sqrt 3\ a

Explanation:

Given that

Lattice constant = a

Radius of unit cell cell =R

Atom is in BCC structure.

In BCC unit cell (Body centered cube)

1.Eight atoms at eight corner of cube which have 1/8 part in each cube.

2.One complete atom at the body center of the cube

So the total number of atoms in the BCC

 Z= 1/8 x 8 + 1 x 1

Z=2

In triangle ABD

AB^2=AD^2+BD^2

AB^2=a^2+a^2

AB=\sqrt 2\ a

In triangle ABC

AC^2=AB^2+BC^2

AC=4R

BC=a

AB=\sqrt 2\ a

So

16R^2=2a^2+a^2

4\ R=\sqrt 3\ a

So the relationship between lattice constant and radius of unit cell

4\ R=\sqrt 3\ a

7 0
3 years ago
If you measured a pressure difference of 50 mm of mercury across a pitot tube placed in a wind tunnel with 200 mm diameter, what
mart [117]

Answer:

V=33.66 m/s

Re=448.8\times 10^6

Re>4000, The flow is turbulent flow.

Explanation:

Given that

Pressure difference  = 50 mm of Hg

We know that density of Hg=136000Kg/m^3

ΔP= 13.6 x 1000 x 0.05 Pa

ΔP=680 Pa

Diameter of tunnel = 200 mm

Property of air at 25°C

ρ=1.2Kg/m^3

Dynamic viscosity

\mu =1.8\times 10^{-8}\ Pa.s

Velocity of fluid given as

V=\sqrt{\dfrac{2\Delta P}{\rho_{air}}}

V=\sqrt{\dfrac{2\times 680}{1.2}}

V=33.66 m/s

Reynolds number

Re=\dfrac{\rho _{air}Vd}{\mu }

Re=\dfrac{1.2\times 33.66\times 0.2}{1.8\times 10^{-8}}

Re=448.8\times 10^6

Re>4000,So the flow is turbulent flow.

4 0
3 years ago
Other questions:
  • 2. When manipulating your pedals, you should use your
    7·2 answers
  • What is the difference between a job and a profession
    9·1 answer
  • One who is trained in math, science and physics in order to work in a branch of engineering
    7·2 answers
  • This app, I'm done, bye... I can't, bye
    11·1 answer
  • Is an ideal way for a high school student to see what an engineer does on a typical day but does not provide a hands-on experien
    9·2 answers
  • Complete the sentence to identify a useful advance in the culinary arts.
    8·1 answer
  • It describes the physical and social elements common to this work. Note that common contexts are listed toward the top, and less
    10·2 answers
  • PLZZZZZ HELP
    10·2 answers
  • A hemispherical shell with an external diameter of 500 mm and a thickness of 20 mm is going to be made by casting, located entir
    12·1 answer
  • Using the tables for water, determine the specified property data at the indicated states. In each case, locate the state on ske
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!