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3 years ago

7. Which of the following is a disadvantage of an electromagnet?

Engineering

1 answer:

Sati [7]3 years ago

7 0

Answer:

I think

electromagnets require power to operate

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Una frase de: ama la vida quien___________________________________

TEA [102]

Answer:

A phrase from: who loves life

Explanation:

5 0

3 years ago

A task is something that you can physically do.

Jet001 [13]

The answer is T because a task is getting something done

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3 years ago

Read 2 more answers

What is the purpose of a gusset or gusset plate used in the construction and repair of aircraft structures?

spin [16.1K]

Answer:

To join and reinforce intersecting structural members

Explanation:

The purpose of a gusset or gusset plate used in the construction and repair of aircraft structures is to join and reinforce intersecting structural members

5 0

2 years ago

Lets assume, a represents the edge length (lattice constant) of a BCC unit cell and R represents the radius of the atom in the u

uranmaximum [27]

Answer:

$4\ R=\sqrt 3\ a$

Explanation:

Given that

Lattice constant = a

Radius of unit cell cell =R

Atom is in BCC structure.

In BCC unit cell (Body centered cube)

1.Eight atoms at eight corner of cube which have 1/8 part in each cube.

2.One complete atom at the body center of the cube

So the total number of atoms in the BCC

Z= 1/8 x 8 + 1 x 1

Z=2

In triangle ABD

$AB^2=AD^2+BD^2$

$AB^2=a^2+a^2$

$AB=\sqrt 2\ a$

In triangle ABC

$AC^2=AB^2+BC^2$

AC=4R

BC=a

$AB=\sqrt 2\ a$

$16R^2=2a^2+a^2$

$4\ R=\sqrt 3\ a$

So the relationship between lattice constant and radius of unit cell

$4\ R=\sqrt 3\ a$

7 0

3 years ago

If you measured a pressure difference of 50 mm of mercury across a pitot tube placed in a wind tunnel with 200 mm diameter, what

mart [117]

Answer:

V=33.66 m/s

$Re=448.8\times 10^6$

Re>4000, The flow is turbulent flow.

Explanation:

Given that

Pressure difference = 50 mm of Hg

We know that density of Hg=136000 $Kg/m^3$

ΔP= 13.6 x 1000 x 0.05 Pa

ΔP=680 Pa

Diameter of tunnel = 200 mm

Property of air at 25°C

ρ=1.2 $Kg/m^3$

Dynamic viscosity

$\mu =1.8\times 10^{-8}\ Pa.s$

Velocity of fluid given as

$V=\sqrt{\dfrac{2\Delta P}{\rho_{air}}}$

$V=\sqrt{\dfrac{2\times 680}{1.2}}$

V=33.66 m/s

Reynolds number

$Re=\dfrac{\rho _{air}Vd}{\mu }$

$Re=\dfrac{1.2\times 33.66\times 0.2}{1.8\times 10^{-8}}$

$Re=448.8\times 10^6$

Re>4000,So the flow is turbulent flow.

4 0

3 years ago