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FromTheMoon [43]
4 years ago
10

What is the last step to the design process?

Engineering
1 answer:
ryzh [129]4 years ago
4 0

Answer:

B: Present solution

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The pressure in a water line is 1500 kPa. What is the line pressure in (a) lb/ft2units and (b) lbf/in2(psi) units?
n200080 [17]

Answer:

Part A:

1500\ KPa= 31328.145 \frac{lb}{ft^2}

Part B:

1500 KPa=217.55656 \frac{lb}{in^2}(Psi)

Explanation:

Part A:

Line Pressure is 1500 KPa

We need a conversion factor which converts KPa to lb/ft^2.

20.88543 \frac{lb}{ft^2}= 1\ KPa

In order to convert 1500 KPa to lb/ft^2, we proceed as:

1\ KPa=20.88543 \frac{lb}{ft^2} \\1500\ KPa= 1500 KPa*20.88543 \frac{lb}{ft^2.KPa}\\1500\ KPa= 31328.145 \frac{lb}{ft^2}

1500 KPa is 31328.145 lb/ft^2

Part B:

We will use the same procedure we did in Part A:

1 ft= 12 in

(1\ ft)^2=(12\ in)^2\\1 ft^2=144 in^2

Converting 1500 KPa\  into\  \frac{lb}{in^2}

1500\ KPa= 1500 KPa*20.88543 \frac{lb}{ft^2.KPa} * \frac{ft^2}{144\ in^2}

1500 KPa=217.55656 \frac{lb}{in^2}(Psi)

1500 KPa is 217.55656 lb/in^2 (psi)

3 0
3 years ago
Three parallel three-phase loads are supplied from a 480V (line-line RMS), 60 Hz three-phase supply. The loads are as follows: L
Travka [436]

Answer:

The total system active power P = P_1 + P_2 + P_3 = 34.91 KW

Explanation:

Load 1: Active power P_1 = 20 HP = 14.91kW;

Reactive power Q1 = P tan(\phi)

                               = 14.91\times tan(cos^{-}0.8) = 11.18 kvar


Load 2: Active power P_2 = 20 kW;

Reactive power Q2 = 0 since the load is purely resistive.

Load 3: Active power P_3 = 0 due to purely capacitiveload

           Reactive power Q_3 = -20 Var

a) since all three loads are connected in parallel therefore

    The total system active power P = P_1 + P_2 + P_3 = 34.91 KW

Total system reactive power Q = Q_1 + Q_2 + Q_3 = 11.18 + 0 -20 = -8.82 kVar

Since Q = 0, the power factor is unity.

Supply current per phase is given by

I = \frac{P}{\sqrt{3}V_{L}}

= \frac{34910}{\sqrt{3}\times 480} = 41.99 A

5 0
3 years ago
Sheet metal cutting operation along a straight line between two cutting edges is called Shearing Operation's. a)- True b)-False
AURORKA [14]

Answer: True

Explanation: The process in sheet metal which separates the metal sheet in straight line by cutting is known as shearing operation.The process of shearing is carried out by application of shearing forces on the metal sheet. this operation separates the metal sheet into two parts by the edges. They have the certain limited tolerance. Therefore the given statement in the question is true.

8 0
4 years ago
A three-phase voltage source with a terminal voltage of 22kV is connected to a three-phase transformer rated 5MVA 22kV/220V. The
amid [387]

Answer:

A) See Attachment B) See Attachment C) 186.153

Explanation:

C) Per phase Voltage= 220/∛3

                                  = 6.037

S=V²/Z

  = (6.037)²/(0.01+i0.05)

  = 62051.282-i310256.41

Active power losses per phase= 62.051kW

total Active power losses= 62.051×3

                                         =186.153kW

6 0
4 years ago
What is reciprocity?
Murrr4er [49]

Answer:

the practice of exchanging things with others for mutual benefit, especially privileges granted by one country or organization to another.

HOPE THIS HELPED!!!!!!!!!!!!! XDDDDDD

7 0
4 years ago
Read 2 more answers
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