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3 years ago

The undisturbed soil at given borrow pit is found to have the following property:

Engineering

1 answer:

tankabanditka [31]3 years ago

7 0

Answer:

Check the explanation

Explanation:

Determine the weight o ids in the each truck °slim the relation,

W,= $\frac{W}{1+w}$

Here, W is net weight of soil and water on the truck and w is water content

substitute 72 7 kN for W and 15% for w.

you will need to also determine the number of truck loads required using the relation:

Number of truck loads required = $\frac{W_{sc} }{W_{s}}$

Kindly check the attached image below for the full explanation to the question above.

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3 years ago

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Poached eggs are cooked in bath of boiling water at 100°C. Over time they reach thermal equilibrium with the bath. They are then

andrew11 [14]

Answer:

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3 years ago

6.27 LAB: Convert to binary - functions Write a program that takes in a positive integer as input, and outputs a string of 1's a

Olin [163]

Answer:

//Convert any decimal number to binary number

//Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include <iostream>

using namespace std;

// Main Method declared here

int main()

{

int x;

cout<<"Enter any integer number: ";

cin>>x;

DecBin(x);

return 0;

}

// Here a function named DecBin is declared along with an integer variable, x

void DecBin(int x)

{

// Declare an array to store the resulting binary digits

int bindigit[32];

// counter for binary array

int kount = 0;

while (x > 0) {

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bindigit[kount] = x % 2;

x = x / 2;

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3 years ago

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm (0.60 in. × 0.75 in.) is pulled in tension with 44,500

lukranit [14]

Answer:

The resulting strain is $1.39\times 10^{-3}$ .

Explanation:

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm

Force, F = 44,500 N

Th elastic modulus of Cu to be 110 GPa

The resulting strain is given by the formula as follows :

$\epsilon=\dfrac{F}{AE}$

E is elastic modulus of Cu is are of cross section

$\epsilon=\dfrac{44500}{15.2\times 19.1\times 10^{-6}\times 110\times 10^9}\\\\\epsilon=1.39\times 10^{-3}$

So, the resulting strain is $1.39\times 10^{-3}$ .

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4 years ago

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vladimir2022 [97]

Answer:

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3 years ago