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professor190 [17]
2 years ago
8

A mixture of gases at 2.99 atm can You have two gases, and , at the same temperature. Determine the ratio of effusion rates of a

nd .ists of 13.2 moles of hydrogen gas and 19.1 moles of helium gas. Determine the partial pressure of the helium gas.
Chemistry
1 answer:
san4es73 [151]2 years ago
3 0

Answer:

Given total pressure of the gas mixture(hydrogen and helium) is 2.99 atm

Number of moles of hydrogen is ---- 13.2 mol

Number of moles of helium is ---- 19.1 mol

Determine the partial pressure of the helium gas.

Ratio of effusion rates of the two gases.

Explanation:

According to Dalton's law of partial pressures,

partial pressure of a component gas in a mixture is:

partial pressure of a gas = total pressure x mole fraction

mole fraction of helium gas is:

mole fraction of helium gas = \frac{number of moles of helium gas}{total number of mioles} \\=>mole fraction of He= \frac{19.1mol}{(19.1+13.2)mol} \\=>mole fraction of He = 0.591\\

Partial pressure of He gas is:

Partial pressure of He =mole fraction of He * total pressure\\                                      =0.591 x 2.99atm\\                                      =1.77atm

Effusion rate of a gas is inversely proportional to its square root of its molecular mass.

\frac{rate of effusion of H2 gas}{rate of effusion of He gas} =\sqrt{\frac{molar mass of He gas}{molar mass of H2 gas} } \\=> \frac{rate of effusion of H2 gas}{rate of effusion of He gas}=\sqrt{\frac{4g.}{2g} } \\=>\frac{rate of effusion of H2 gas}{rate of effusion of He gas}=1.414:1

Hence, rates of effusion of H2:He is 1.414:1.

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