The accurate description of the process of erosion is when <span>moving bits of rock and soil across the earth’s surface by water, wind, or glaciers. The answer is letter C.</span>
B.
technically it would depend if the resistors were in series or parallel but B is the answer.
Answer:

Explanation:
As we know that when electron moved in electric field then work done by electric field must be equal to the change in kinetic energy of the electron
So here we have to find the work done by electric field on moving electron
So we have



now the distance moved by the electron is given as

so we have



now we have to convert it into keV units
so we have


Lipids and <span>Polysaccharides r the answers hoped i helped</span>