Answer;
D. The group number is equal to the number of valence electrons.
Explanation;
-The valence electrons are the electrons in the outer shell of an atom. The valence electrons are the ones involved in forming bonds to adjacent atoms. Therefore, the number of valence electrons is important for determining the number of bonds an atom will form, the number of unpaired electrons, and an atom’s formal charge.
-For neutral atoms, the number of valence electrons is equal to the atom’s main group number.
Number of valence electrons = main group number (neutral atoms)
-The main group number for an element can be found from its column on the periodic table. For example, carbon is in group 4 and has 4 valence electrons. Oxygen is in group 6 and has 6 valence electrons.
Answer:
B
Explanation:
a straight yellow is a no pass zone
Answer:
0.45 m/s in the negative x-direction
Explanation:
From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum
Momentum, p=mv where m is the mass and v is the velocity
where
is the common velocity,
and
are velocities of magnet moving in positive x-direction and magnet moving in negative x-direction respectively,
and
are masses of magnet moving in positive x-direction and magnet moving in negative x-direction respectively.
Substituting 125 g for
and 85 g for
, 7.33 m/s
, -11.9 m/s for
then
![125 g\times 7.33 m/s + (85 g\times -11.9)=(125 g+ 85 g)\times v_c](https://tex.z-dn.net/?f=125%20g%5Ctimes%207.33%20m%2Fs%20%2B%20%2885%20g%5Ctimes%20-11.9%29%3D%28125%20g%2B%2085%20g%29%5Ctimes%20v_c)
![-95.25 g. m/s=210 g v_c](https://tex.z-dn.net/?f=-95.25%20g.%20m%2Fs%3D210%20g%20v_c)
![v_c=\frac {-95.25 g.m/s}{210 g}=-0.453571429 m/s \approx -0.45 m/s](https://tex.z-dn.net/?f=v_c%3D%5Cfrac%20%7B-95.25%20g.m%2Fs%7D%7B210%20g%7D%3D-0.453571429%20m%2Fs%0A%5Capprox%20-0.45%20m%2Fs)
Therefore, the velocity of single unit is 0.45 m/s in the negative x-direction
In a forward bias, the p-type is connected to the positive side of the terminal and the n-type is connected to the negative terminal of the voltage source. The electrons in the n-type junction travels towards the holes in the p-type junction
In a reverse bias, the junctions are connected to the opposite terminals compared to the forward bias. The free electrons build up on the center creating a neutral layer that widens as voltage is increased.
The reactions of the citric acid cycle that provide reducing power for the electron‑transport chain are as follows:
- Conversion of isocitrate to α-ketoglutarate
- Conversion of succinate to fumarate
- Conversion of α-ketoglutarate to succinyl-coA
<h3>
What is citric acid cycle?</h3>
Citric acid cycle also known as kreb cycle is a series of biochemical reactions that involves the synthesis of reduced electron carrier and ATP.
The following steps in the citric acid cycle involves the provision of reducing power for the electron‑transport chain:
- Conversion of isocitrate to α-ketoglutarate: Isocitrate is converted to α-ketoglutarate as catalyzed by isocitrate dehydrogenase.
- Conversion of α-ketoglutarate to succinyl-coA: α-ketoglutarate is converted to succinyl-coA as catalyzed by α-ketoglutarate dehydrogenase.
Learn more about citric acid cycle: brainly.com/question/11459709