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Murrr4er [49]
3 years ago
5

In a tight circular turn, a falcon can attain a centripetal acceleration 1.5 times free-fall acceleration. What is the radius of

the turn if the falcon is flying at 22 m/s?
Physics
1 answer:
ycow [4]3 years ago
6 0

Answer:

32.925 m.

Explanation:

The formula of  centripetal acceleration is

a = v²/r ............... Equation 1

Where a = centripetal acceleration, v = linear velocity, r = radius.

make r the subject of the equation.

r = a/v²............. Equation 2

Given: v = 22 m/s,

a = 1.5 times free fall acceleration

Note: Free fall = 9.8 m/s²

Therefore, a = 1.5×9.8 = 14.7 m/s²

Substitute into equation 2

r = 22²/14.7

r = 484/14.7

r = 32.925 m.

Hence the radius of the turn = 32.925 m.

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The detailed steps and calculation is shown in the attachment.

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Part D- Isolating a Variable with a Coefficient In some cases, neither of the two equations in the system will contain a variabl
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D)     D = \frac{5}{4}  - \frac{3}{4} \ C, E)  (C, D) = ( \frac{17}{7}, \ \frac{-4}{7}

Explanation:

Part D) two expressions are indicated

          3C + 4D = 5

          2C +5 D = 2

let's simplify each expression

         3C + 4D = 5

         4D = 5 - 3C

we divide by 4

            D = \frac{5}{4}  - \frac{3}{4} \ C

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we can see that the correct result is 1

Part E.

It is asked to solve the problem by the substitution method, we already have

          D =  \frac{5}{4}  - \frac{3}{4} \ C

we substitute in the other equation

            2C +5 D = 2

             2C +5 (5/4 - ¾ C) = 2

we solve

            C (2 - 15/4) + 25/4 = 2

             -7 / 4 C = 2 - 25/4

             -7 / 4 C = -17/4

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               C = \frac{17}{7}

now we calculate D

               D = \frac{5}{4} - \frac{3}{4} \ \frac{17}{7}

               D = 5/4 - 51/28

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               D = - \frac{4}{7}

the result is (C, D) = ( \frac{17}{7}, \ \frac{-4}{7} )

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