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Murrr4er [49]
3 years ago
5

In a tight circular turn, a falcon can attain a centripetal acceleration 1.5 times free-fall acceleration. What is the radius of

the turn if the falcon is flying at 22 m/s?
Physics
1 answer:
ycow [4]3 years ago
6 0

Answer:

32.925 m.

Explanation:

The formula of  centripetal acceleration is

a = v²/r ............... Equation 1

Where a = centripetal acceleration, v = linear velocity, r = radius.

make r the subject of the equation.

r = a/v²............. Equation 2

Given: v = 22 m/s,

a = 1.5 times free fall acceleration

Note: Free fall = 9.8 m/s²

Therefore, a = 1.5×9.8 = 14.7 m/s²

Substitute into equation 2

r = 22²/14.7

r = 484/14.7

r = 32.925 m.

Hence the radius of the turn = 32.925 m.

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6 0
2 years ago
An object is moving with a constant velocity of 278 m/s. How long will it take it to travel 7500 m, using the formula Delta X=Vt
rusak2 [61]
If the velocity is constant then the acceleration of the object is zero.
a=0 (m/s^2)
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7 0
4 years ago
Two positive point charges of 12uc and Suc
GarryVolchara [31]

Answer:

54 N

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We have two positive charges 12uC and 5 uC ,they are kept at a distance of 10cm.

We have a relation for force between two charges q1,q2 as

F=\frac{kq1q2}{r^{2} }

Value of k is 9*10^9

On substituting the values into the equation we get,

F=\frac{9*10^9*12*5}{10^9*10}\\\\  F=54N

Hence the force between them is 54 N.

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3 years ago
Explain three differences between a science and a pseudoscience.
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Answer:

C.

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6 0
3 years ago
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