Question

The mass fraction of eutectoid cementite in a hypoeutectoid iron-carbon alloy (just below its eutectoid temperature) is 0.109. On the basis of this information, determine the composition of the alloy. If it is not possible to determine the composition from the information provided, enter 0.

Answer 1

Answer:

The composition of an alloy is 0.75%wt

Explanation:

Let alloy is a hypoeutectoid alloy.

So, we can apply lever rule which is shown below.

$W_{a}=$$\frac{C_{0} -C_{a} }{C_{b}-C_{a} }$

We know that $C_{a}=0.022$ and $C_{b}=6.7$

Given that $W_{a}=0.109$, we have to find $C_{0}$

Thus,

$0.109=\frac{C_{0}-0.022 }{6.7-0.022}$

Hence

$C_{0}=0.75$%wt