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ahrayia [7]
3 years ago
10

The Bureau of Labor and Statistics predicted that the field of biomedical engineering would increase by 62 percent over the comi

ng decade. What should this most likely mean?
Doctors across the country are relying on biomedical engineers to perform more of their own job functions.

It is an out-of-date profession that students should not consider pursuing.

It is a continually growing field, and individuals trained in it should not have a problem finding employment.

It is the most popular area of engineering.
Engineering
1 answer:
raketka [301]3 years ago
5 0

Answer:

C. It is a continually growing field, and individuals trained in it should not have a problem finding employment.

Explanation:

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18. Bela is doing a continuity test. What's he checking?
murzikaleks [220]

Answer:

the bela is doing a continuity test he checking current

8 0
2 years ago
A tire-pressure monitoring system warns you with a dashboard alert when one of your car tires is significantly under-inflated.
chubhunter [2.5K]

Answer:

The answers to the question are

(a) T = 2·π·r/v

(b) 3.3 % change in period of the under-inflated tire compared to the properly inflated tire

(c) Therefore the distance this car would have to travel in order for under-inflated tire to make one more complete rotation than the inflated tire is 57.685 meters.

Explanation:

(a) The period T = 2π/ω

The velocity v = ωr or ω = v/r

Therefore T = 2π/(v/r) = 2πr/v

T = 2·π·r/v

(b) Period of properly inflated tire with radius = 303 mm is 2π303/v

Period of under-inflated tire with radius = 293 mm is 2π293/v

Therefore we have percentage change in period of  of the under-inflated tire compared to the properly inflated tire is given by

(2π303/v -2π293/v)/(2π303/v) = 2π10/v/(2π303/v) = 10/303 × 100 = 3.3 %

(c) The period of the under-inflated tire is 10/303 less than that of the inflated tire. Therefore for the under-inflated tire to make one complete turn more than the inflated tire, we have 1/(10/303)  = 303/10 or 30.3 revolutions of either tire which is 30.3×2×π×303 = 57685.296 mm = 57.685 meters

Therefore the distance this car would have to travel in order for under-inflated tire to make one more complete rotation than the inflated tire is 57.685 meters

At 30.3 revolutions the distance covered by the under-inflated

= 55781.49 mm

Subtracting the two distances gives

1903.805 mm

The circumference of the inflated tire = 2×π×303 = 1903.805 mm

3 0
3 years ago
6. Question
valkas [14]

Answer:

Check  the 2nd, 3rd and 4th statements.

Explanation:

4 0
3 years ago
The inspector should inspect insulation in unfinished spaces, including attics, _____ and foundation areas.
RoseWind [281]

Answer:

basements

Explanation:

6 0
2 years ago
A smooth ceramic sphere (SG 5 2.6) is immersed in a fl ow of water at 208C and 25 cm/s. What is the sphere diameter if it is enc
Aleks [24]

Answer:

a. 4\mu m

b. 1 m

Explanation:

According to the question, the data is as follows

The Density of water at 20 degrees celcius is 1000 kg/m^3

Viscosity is 0.001kg/m/.s

Velocity V = 25 cm/s

V = 0.25 m/s

Now

a. The creeping motion is

As we know that

Reynold Number = (Density of water × V × d) ÷ (Viscosity)

1 = (1,000 × 0.25 × d) ÷ 0.0001

d = (1 × 0.001) ÷ (1,000 × 0.25)

= 4E - 06^m

= 4\mu m

b. Now the sphere diameter is

Reynold Number = (Density of water × V × d) ÷ (Viscosity)

250,000 = (1,000 × 0.25 × d) ÷ 0.0001

d = (250,000 × 0.001) ÷ (1,000 × 0.25)

= 1 m

6 0
3 years ago
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