The final volume V₂=4.962 L
<h3>Further explanation</h3>
Given
T₁=20 + 273 = 293 K
P₁= 1 atm
V₁ = 4 L
T₂=100+273 = 373 K
P₂=780 torr=1,02632 atm
Required
The final volume
Solution
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
V₂=(P₁V₁T₂)/(P₂T₁)
V₂=(1 x 4 x 373)/(1.02632 x 293)
V₂=4.962 L
Gas particles lose their energy during collisions
Answer : The energy involved in condensation is, 339 kJ
Explanation :
Formula used :

where,
q = heat required = ?
L = latent heat of vaporization of water = 
m = mass of water = 150 g
Now put all the given values in the above formula, we get:


Therefore, the energy involved in condensation is, 339 kJ