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Yanka [14]
2 years ago
6

6th grade science please help!​

Physics
1 answer:
labwork [276]2 years ago
5 0

Answer:

conduction

Explanation:

Conduction transfers heat via direct molecular collision. An area of greater kinetic energy will transfer thermal energy to an area with lower kinetic energy. Higher-speed particles will collide with slower speed particles.

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Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?
noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

k = 9 * 10^9

q_1 = 2pC

q_2 = 4pC

r = 6cm = 0.06 m

now by using the above equation we have

F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}

F = 2 * 10^{-11} N

so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.

3 0
3 years ago
If you decide you want to meet someone you met online, what should you do first?
seraphim [82]

c tell your parents it could be someone very dangerous and meeting people online can be very risky I would also tell my bsf just for fun tho

6 0
3 years ago
What is the total surface charge qint on the interior surface of the conductor (i.e., on the wall of the cavity)
RSB [31]

Answer: hello your question is incomplete below is the missing part

A spherical cavity is hollowed out of the interior of a neutral conducting sphere. At the center of the cavity is a point charge, of positive charge q.

answer:

- q

Explanation:

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given that there is a point charge +q at the center of the spherical cavity hence for the electric field inside the conductor to be = zero the total surface charge qint on the wall of the cavity will be -q

6 0
3 years ago
Thermal energy is added to four identical samples of water what increases in each sample
Setler [38]
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3 years ago
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What force must act on a 50.0-kg mass to give it an ancceleration of 0.30 m/s^2?
ratelena [41]

Answer:

15.0 N

Explanation:

see pic

3 0
2 years ago
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