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Eva8 [605]
2 years ago
8

The bond between which two atoms is most

Chemistry
1 answer:
MariettaO [177]2 years ago
8 0
The answer would be option 4
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I need this asap Molar mass of C6H12O6
Zolol [24]

Answer:

180.156 g/mol

Explanation:

Hopes help

4 0
2 years ago
Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II) chloride.
Marrrta [24]

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

Explanation:

  • The products formed are chromic chloride and cobalt.

        Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt

  • Type  of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.

Reactants used in the reaction are -

  • Chromium(Cr)
  • Cobaltous Chloride (CoCl_2)

Products formed in the reaction are -

  • Chromic Chloride(CrCl_3)
  • Cobalt (Co)

Hence, the chemical reaction is as follows -

  • Cr + CoCl_2 →CrCl_3 + Co

For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.

Hence, the balanced equation is -

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

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3 years ago
What do El Niño and La Niña have in common? Check all that apply.
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2 years ago
How many grams of PbBr2 will precipitate when excess CuBr2 solution is added to 77.0 mL of 0.595 M Pb(NO3)2 solution?Pb(NO3)2(aq
Alexxx [7]

Answer:

16.89g of PbBr2

Explanation:

First, let us calculate the number of mole of Pb(NO3)2. This is illustrated below:

Molarity of Pb(NO3)2 = 0.595M

Volume = 77mL = 77/1000 = 0.077L

Mole =?

Molarity = mole/Volume

Mole = Molarity x Volume

Mole of Pb(NO3)2 = 0.595x0.077

Mole of Pb(NO3)2 = 0.046mol

Convert 0.046mol of Pb(NO3)2 to grams as shown below:

Molar Mass of Pb(NO3)2 =

207 + 2[ 14 + (16x3)]

= 207 + 2[14 + 48]

= 207 + 2[62] = 207 +124 = 331g/mol

Mass of Pb(NO3)2 = number of mole x molar Mass = 0.046 x 331 = 15.23g

Molar Mass of PbBr2 = 207 + (2x80) = 207 + 160 = 367g/mol

Equation for the reaction is given below:

Pb(NO3)2 + CuBr2 —> PbBr2 + Cu(NO3)2

From the equation above,

331g of Pb(NO3)2 precipitated 367g of PbBr2

Therefore, 15.23g of Pb(NO3)2 will precipitate = (15.23x367)/331 = 16.89g of PbBr2

8 0
3 years ago
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